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3 years ago

Which expressions are equivalent to {22c 33d}22c 33d22, c, plus, 33, d? socratic.

Mathematics

1 answer:

kotegsom [21]3 years ago

4 0

Answer:

(-2c-3d) (- 11) (- 2c-3d) (- 11) left parenthesis, minus, 2, c, minus, 3, d, right parenthesis, left parenthesis, minus, 11, right parenthesis

(66c + 99d) \ cdot \ dfrac {1} {3} (66c + 99d) ⋅ 3

1 left parenthesis, 66, c, plus, 99, d, right parenthesis, dot, start fraction, 1, divided by, 3, end fraction

11\cdot(2c+3d)11⋅(2c+3d)11, dot, left parenthesis, 2, c, plus, 3, d, right parenthesis

answer

(-2c-3d) (- 11) = 22c + 33d

(66c + 99d) * 1/3 = 22c + 33d

11 * ( 2c+3d) = 22c + 33d

Step-by-step explanation:

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The work shows the first steps of writing a partial fraction decomposition.

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3 years ago

-5,3,-2,1,-1,0 what is next number

nlexa [21]

Answer:

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3 years ago

PLS HELP WILL MAKE FIRST RIGHT ANSWER BRAINLIEST

Amanda [17]

Answer: -8 is the answer.

Step-by-step explanation:

according to the question:

{{(8+4)*5}/(-10)}-2

= {[12*5}/(-10)]-2

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4 0

2 years ago

Read 2 more answers

The question is the photo

Readme [11.4K]

For this question you can say:
5/9( °F - 32) = -10 °C
so now you should solve the equation:
5F/9 - 160/9 = -10
⇒ 5F/9 = -10 + 160/9 ⇒ 5F/9 = -90/9 + 160/9 ⇒ 5F/9 = 70/9 ⇒ now you can multiply both sides of the equation by 9 so you will have:
5F = 70 ⇒ F = 14 ° F :)))
i hope this is helpful
have a nice day

6 0

3 years ago

Use appropriate algebra and theorem 7.2.1 to find the given inverse laplace transform. (write your answer as a function of t.) ℒ

castortr0y [4]

We assume you want to find the inverse transform of s/(s^2 +3s -4). This can be written in partial fraction form as

(4/5)/(s+4) + (1/5)/(s-1)

which can be found in a table of transforms to be the transform of

(4/5)e^(-4t) + (1/5)e^t

_____

There are a number of ways to determine the partial fractions. They all start with factoring the denominator.

s^2 +3x -4 = (s+4)(s-1)

After that, you can postulate the final form and determine the values of the coefficients that make it so. For example:

A/(s+4) + B/(s-1) = ((A+B)s + (4B-A))/(s^2 +3x -4)

This gives rise to two equations:

(A+B) = 1

(4B-A) = 0

4 0

3 years ago