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Marta_Voda [28]
3 years ago
5

Which expressions are equivalent to {22c 33d}22c 33d22, c, plus, 33, d? socratic.

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0

Answer:

A

(-2c-3d) (- 11) (- 2c-3d) (- 11) left parenthesis, minus, 2, c, minus, 3, d, right parenthesis, left parenthesis, minus, 11, right parenthesis

C

(66c + 99d) \ cdot \ dfrac {1} {3} (66c + 99d) ⋅ 3

1 left parenthesis, 66, c, plus, 99, d, right parenthesis, dot, start fraction, 1, divided by, 3, end fraction

E

11\cdot(2c+3d)11⋅(2c+3d)11, dot, left parenthesis, 2, c, plus, 3, d, right parenthesis

answer

(-2c-3d) (- 11) = 22c + 33d

(66c + 99d) * 1/3 = 22c + 33d

11 * ( 2c+3d) = 22c + 33d

Step-by-step explanation:

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Given:

\lim _{x\to0}\frac{\tan 2x-\sin 2x}{x^3}

Solve:

\lim _{x\to0}\frac{\tan 2x-\sin 2x}{x^3}

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\begin{gathered} =\lim _{x\to0}\frac{\frac{d}{dx}(-\sin 2x+\tan 2x)}{\frac{d}{dx}(x^3)} \\ =\lim _{x\to0}\frac{-2\cos (2x)+2\tan ^2(2x)+2}{3x^2} \end{gathered}

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\begin{gathered} =\lim _{x\to0}\frac{-2\cos (2x)+2\tan ^2(2x)+2}{3x^2} \\ =\lim _{x\to0}\frac{2(-\cos (2x)+\tan ^2(2x)+1)}{3x^2} \end{gathered}

Apply the constant multiple rule:

\begin{gathered} \lim _{x\to0}cf(x)=c\lim _{x\to0}f(x) \\ \text{With c=}\frac{2}{3} \\ f(x)=\frac{-\cos (2x)+\tan ^2(2x)+1}{x^2} \end{gathered}\begin{gathered} =\frac{2\lim _{x\to0}\frac{-\cos (2x)+\tan ^2(2x)+1}{x^2}}{3} \\ =\frac{2\lim _{x\rightarrow0}\frac{(4\tan ^2(2x)+4)\tan (2x)+2\sin (2x)}{2x}}{3} \end{gathered}

Similary :

\begin{gathered} =\frac{2\lim _{x\to0}(2\cos (2x)+12\tan ^4(2x)+16\tan ^2(2x)+4)}{3} \\ =\frac{2(6)}{3} \\ =4 \end{gathered}

8 0
1 year ago
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BabaBlast [244]

<u><em>Answer: </em></u>

Median : 23

Mode: 11 and 24

Range: 28

<u><em> </em></u>

<u><em>Step-by-step explanation: </em></u>

A stem-and- leaf plot is a very special table where each " value" is split into a stem.

Basically the stem is the foirst value of the number and the leaves are the last digits.    

Example: A stem of 1 and a leaf of 1 has a value of 11.

              A stem of 1 and a leaf of 2 has a value of 12.

In this case the numbers in the plot are:

11, 11, 12, 13, 14, 15, 22, 23, 24, 24, 27, 32, 35, 37, 39

The questions are :

<u><em> </em></u>

<u><em>1. What is the median? </em></u>

<u><em>2. What is the mode ? </em></u>

<u><em>3. What is the range ? </em></u>

To answer the first question, you need to list them in order.

Then find the center of those numbers. Cross out one number from the left and the right and keep doing it until there is only one ot two numbers.

One number- that is the median

two numbers left - find the mean of the two numbers and that is the median

So in this case the median is 23 crossing out seven numbers on each side.

To answer the second question, you need to find the number that comes up the most. In this case, 11 and 24.

To answer the third and last question, you need to find the mininum value and the maximum and find the difference.

In this case, 11 and 39, the difference is 28.

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<em>Note: We are using order of operations (consecutively)</em>

  1. <em>Parentheses </em>
  2. <em>Exponents</em>
  3. <em>Multiplication</em>
  4. <em>Division</em>
  5. <em>Addition </em>
  6. <em>Subtraction</em>

Multiply:

25 * 4 = 100

Add:

100 + 3 = 103

Our answer is 103

<em />

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