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yan [13]
3 years ago
8

Is -14 an integer and a rational number?if not why

Mathematics
1 answer:
antoniya [11.8K]3 years ago
3 0

It's not an integer because integers must be positive in order to be rational integers. It can still be considered an integer in some cases, but typically you dount count numbers using negatives, do you?

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Sean bought 8 slurpees at $1.50 each and 6 popsicles. He gave the cashier $25.00 and received $4.00 change. How much did each Po
Lina20 [59]

Answer:

1.50

Step-by-step explanation:

8 x 1.50=12

25-12=13

13-4=9

9/6=1.5

8 0
3 years ago
A teenager earns $10 for every 600 square feet mowed in addition to $12 for supplies for each lawn he mows. Which function repre
anzhelika [568]

Answer: b

Step-by-step explanation: 600 is the total so, just do 10x and 12

5 0
3 years ago
It has been reported that 48% of teenagers play video games on their phones. A random sample of 60 teenages is drawn. Find the p
Ivanshal [37]

Answer:

skakaaja

Step-by-step explanation:

aamnanananan

3 0
3 years ago
Please help!!!! i am despite, i will mark brainlyest
Sedaia [141]

Answer:

x=12

10x = 120

5x = 60

Step-by-step explanation:

paralellograms will become 360 degrees

so 2(5x) +2(10x)= 360

Simplify:

10x + 20x = 360

= 30x

divide both sides by 30 and isolate

<u>30x </u> = <u>360</u>

30        30

x=12

multiply 12 by 10x and 5x

10x = 120

5x = 60

7 0
3 years ago
A game is played with a spinner on a circle, like the minute hand on a clock. The circle is marked evenly from 0 to 100, so, for
zheka24 [161]

Answer:

The probability is 1/2

Step-by-step explanation:

The time a person is given corresponds to a uniform distribution with values between 0 and 100. The mean of this distribution is 0+100/2 = 50 and the variance is (100-0)²/12 = 833.3.

When we take 100 players we are taking 100 independent samples from this same random variable. The mean sample, lets call it X, has equal mean but the variance is equal to the variance divided by the length of the sample, hence it is 833.3/100 = 8.333.

As a consecuence of the Central Limit Theorem, the mean sample (taken from independant identically distributed random variables) has distribution Normal with parameters μ = 50, σ= 8.333. We take the standarization of X, calling it W, whose distribution is Normal Standard, in other words

W = \frac{X - \mu}{\sigma} = \frac{X - 50}{8.333} \simeq N(0,1)

The values of the cummulative distribution of the Standard Normal distribution, lets denote it \phi , are tabulated and they can be found in the attached file, We want to know when X is above 50, we can solve that by using the standarization

P(X > 50) = P(\frac{X-50}{8.33} > \frac{50-50}{8.33}) = P(W > 0) = \phi(0) = 1/2

Download pdf
8 0
3 years ago
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