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IrinaK [193]
3 years ago
5

Finn bought a yoyo from a company that claims that, with each retraction, the string rolls up by 80% of the original length. He

sets up a tape measure and throws the yoyo 3 times. His data are charted below.
Throw Length of string (feet)
1 3
2 2.4
3 1.92
Finn wants to find the sum of the length of string after 10 throws. What is the sum of the lengths, rounded to the nearest hundredth?
Mathematics
1 answer:
lubasha [3.4K]3 years ago
8 0
<span><span /><span><span>1st      3 <span>                      0.80 </span> <span>                 2.40 </span> </span> <span> <span>                   
2nd     2.40 </span> <span>                 0.80 </span> <span>                 1.92 </span> </span> <span> <span>                   
3rd     1.92 </span> <span>                 0.80 </span> <span>                 1.54 </span> </span> <span> <span>                   
4th     1.54 </span> <span>                 0.80 </span> <span>                 1.23 </span> </span> <span> <span>                   
5th     1.23 </span> <span>                 0.80 </span> <span>                 0.98 </span> </span> <span> <span>                   
6th     0.98 </span> <span>                 0.80 </span> <span>                 0.79 </span> </span> <span> <span>                   
7th     0.79 </span> <span>                 0.80 </span> <span>                 0.63 </span> </span> <span> <span>                   
8th     0.63 </span> <span>                 0.80 </span> <span>                 0.50 </span> </span> <span> <span>                   
9th     0.50 </span> <span>                 0.80 </span> <span>                 0.40 </span> </span> <span> <span>                   
10th   0.40 </span> <span>                 0.80 </span> <span>                 0.32
total:  13.39

13.39 rounded to 13.40 is the sum of the length of string after 10 throws.

Based on the table: I generated the formula:

f(x) = 3 
</span></span></span></span>×<span><span><span><span> 0.80</span></span></span></span>ˣ

where the exponent x represents the number of throws.
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Let 
x = number of liters of the 40% salt solution 
y = number of liters of the 20% salt solution 

The two amounts (x and y) must combine to 1500 liters, so 
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we can solve for y to get
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---------------------------------------------------

If we have x liters of the 40% salt solution (composed of pure salt plus other stuff) then we have exactly 0.40*x liters of pure salt. Simply multiply the decimal form of the percentage with the amount of solution. 

Similarly, if we have y liters of the 20% solution, then we have 0.20*y liters of pure salt

Combined, we have 0.40*x + 0.20*y liters of pure salt all together. 

We want 1500 liters of a 28% solution, so we want 1500*0.28 = 420 liters of pure salt

Equate the two expressions (0.40*x + 0.20*y and 420) to get
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---------------------------------------------------

We have the equation 0.40*x + 0.20*y = 420 and we also know that y = 1500-x

Let's use the substitution property now

0.40*x + 0.20*y = 420
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Now we can solve for x
0.40*x + 0.20*( 1500 - x ) = 420
0.40*x + 0.20*(1500) + 0.20*(-x) = 420
0.40*x + 300 - 0.20x = 420
0.40*x - 0.20x + 300 = 420
0.20x + 300 = 420
0.20x + 300 - 300 = 420 - 300
0.20x = 120
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Now that we know x, use this to find y
y = 1500-x
y = 1500-600 ... plug in x = 600 (ie replace x with 600)
y = 900
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Answers:

We need 600 liters of the 40% solution
We need 900 liters of the 20% solution

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