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MariettaO [177]
3 years ago
13

What is the solution to 3x+2=x+8

Mathematics
1 answer:
dedylja [7]3 years ago
6 0
That’s the answer and i showed the work hoped this helped!!!

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Paul can install a 300 hundred square foot hardwood floor in 18 hours. Matt can install the same floor in 22 hours. How long wou
Vadim26 [7]
ANSWER

Paul and Matt will take
9.9 \: \: hours
to install the floor working together.

EXPLANATION

First, calculate Paul's rate, which is

= \frac{1}{18}

Next, calculate Matt's rate, which is,
= \frac{1}{22}

Let us assume that, Paul and Matt took
x \: hours
to do the work together.

Then, the rate of working together is,

= \frac{1}{x}

Now, add the individual rates and equate to the rate of working together to form an equation that will help us solve for x.

\frac{1}{18} + \frac{1}{22} = \frac{1}{x}

Simplify the left hand side

\frac{11 + 9}{198} = \frac{1}{x}

\frac{20}{198} = \frac{1}{x}

We reciprocate both sides to get (You could have also done cross multiplication).

\frac{198}{20} = \frac{x}{1}

x = 9.9 \: hours
7 0
3 years ago
Simplify −4√−48<br> Help , please ?
Talja [164]
The answer is -16 radical 3
4 0
3 years ago
Find the distance between the points
Tasya [4]

Answer:

5 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (2, 1) and (x₂, y₂ ) = (6, 4)

d = \sqrt{(6-2)^2+(4-1)^2}

   = \sqrt{4^2+3^2}

   = \sqrt{16+9}

    = \sqrt{25}

    = 5

3 0
3 years ago
Read 2 more answers
Put Y=x^2+10x+18 in vertex form
nika2105 [10]

Answer:(-5,-7)

Step-by-step explanation:

Rewrite in Vertex form and use this form to find the vertex (h,k)

4 0
3 years ago
Read 2 more answers
A student finished 72 of her homework problems in class. If the ratio of problems she finished to problems she still had left wa
kramer


Finished:Left

8:1

8/1 = 72/x

Cross Multiply

8x=72

divide each side by 8

x=9

She already finished 72 and has 9 remaining

Total = Finished + Remaining = 72 + 9 = 81

4 0
3 years ago
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