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4 years ago

Please help ASAP!!

Mathematics

1 answer:

soldi70 [24.7K]4 years ago

7 0

Hello again!

Corresponding sides:

AD and DB

AC and BC

CD and CD

Corresponding angles:

<CDA and <CDB

<CAD and <CBD

<DCA and <DCB

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1) write a system on equations with the solution (2, -3). Work the problem out using the substitution method

solmaris [256]

The system of the equations that have the solution of (2, -3) are given below.

3x + 2y = 0 and 3y = 2x - 13

<h3>What is the linear system?</h3>

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

Write a system of equations with the solution (2, -3).

From a single point, an infinite number of lines pass through this point.

Let one line is passing through the origin. Then the equation of the line will be

$\rm y = \dfrac{-3}{2} (x)\\\\y = -1.5x$

And the other line is perpendicular to the line which is passing through the origin and a point (2, -3).

$\rm y = \dfrac{2}{3} x + c$

Then this line also passes through a point (2, -3). Then the value of c will be

$\rm -3 = \dfrac{2}{3} \times 2 + c\\\\c \ \ = -13$

Then the equation of the line will be

3y = 2x -13

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ4

8 0

2 years ago

Use the above graph to answer the following:

igor_vitrenko [27]

Slope of the line is -4/5, y-intercept is 3, equation in slope-intercept form is y = -4/5 x + 3 and the x-intercept is 15/4

Step-by-step explanation:

Step 1: Find slope, m.

Slope = (y2 - y1)/(x2 - x1)

Here, x1 = 0, y1 = 3, x2 = 5, y2 = -1 (based on the plotted points)

⇒ m = (-1 - 3)/(5 - 0) = -4/5

Step 2: Find the y-intercept

y-intercept is the point where the line intersects the y-axis.

Here, the y-intercept, b = 3

Step 3: Write the equation of the line in slope-intercept form

y = mx + b ⇒ y = -4/5 x + 3

Step 4: Find the x-intercept using the equation.

x-intercept is the point where the line intersects the x-axis. Then y = 0

⇒ 0 = -4/5 × x + 3

⇒ -4/5 × x = -3

⇒4x = 15

∴ x = 15/4

6 0

4 years ago

Consider two quantities u and v that are related by the expression vp=cuq, where c is a constant. the exponents p and q are not

Mazyrski [523]

Answer:

y = (q/p)x +log(c)/p

Step-by-step explanation:

$v^{p}=cu^{q}\qquad\text{original equation}\\\\p\log{(v)}=\log{(c)}+q\log{(u)}\qquad\text{take the log}\\\\py=log{(c)}+qx\qquad\text{substitute x and y}\\\\y=\dfrac{\log{(c)}+qx}{p}$

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3 years ago

Alana’s baby brother weighed 137 oz when he was born. What is his weight in pounds<br> and ounces?

OverLord2011 [107]

8 pounds and 562 oz

4 0

3 years ago

Graph the function xy+25=0

Likurg_2 [28]

This is the same as saying x*y+25=0.

Also, x*y=-25.

The solution (if you had to find it) would be -5 and 5.

To graph, it would be y=-25/x

Edit: This can be simplified down to y=-5 since it is a constant so it would be a straight line on the y-axis down at -5.

4 0

3 years ago

Read 2 more answers