Answer:
f(x) < –x2 + x – 1
Step-by-step explanation:
The graph is going down so we know that there is a maximum, therefore the A value has to be negative. This rules out f(x) < x2 + x – 1 and f(x) > x2 + x – 1
. The shaded area of the graph is below which indicates that f(x) has to be less than the function. This means the correct answer is f(x) < –x2 + x – 1 .
Answer:10/7 and mixed number form is 1 3/7
So to set up the equation we have:
<span><span><span>4M</span><span>4+M</span></span>=<span>127</span></span>
<span>28M=12(4+M)</span>
<span>28M=48+12M</span>
<span>28K−12M=48</span>
<span>(28−12)M=48</span>
<span>16K=48</span>
<span>M=<span>4816</span></span>
<span>M=3</span>
So Marna can clean the chimney alone in 3 hours
Hi There!
Answer:
$18.25 per hour.
Step-by-step explanation:
365 / 20 = 18.25 (hourly pay)
1500 * 0.16 = 240 (comission)
Hope This Helps :)
Answer:
![Probability = \frac{1}{6}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%7D%7B6%7D)
Step-by-step explanation:
Given
The above table
Required
Determine the probability of a sum that is a multiple of 6
Represent the event that an outcome is a multiple of 6 with M.
List out all possible values of M
![M = \{6,6,6,6,6,12\}](https://tex.z-dn.net/?f=M%20%3D%20%5C%7B6%2C6%2C6%2C6%2C6%2C12%5C%7D)
Number of M is
![n(M) = 6](https://tex.z-dn.net/?f=n%28M%29%20%3D%206)
Total possible outcome is:
![n(Total) = 36](https://tex.z-dn.net/?f=n%28Total%29%20%3D%2036)
The theoretical probability is then calculated as follows:
![Probability = \frac{Number\ of\ desired\ outcomes}{Number\ of\ possible\ outcomes}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7BNumber%5C%20of%5C%20desired%5C%20outcomes%7D%7BNumber%5C%20of%5C%20possible%5C%20outcomes%7D)
In this case, it is:
![Probability = \frac{n(M)}{n(Total)}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7Bn%28M%29%7D%7Bn%28Total%29%7D)
![Probability = \frac{6}{36}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B6%7D%7B36%7D)
Simplify fraction
![Probability = \frac{1}{6}](https://tex.z-dn.net/?f=Probability%20%3D%20%5Cfrac%7B1%7D%7B6%7D)