Answer:
Radius of aluminium sphere which has same mass as of sphere of iron with radius 14 m is 40.745 meters.
Explanation:
Let the radius of aluminium sphere be
From the relation between density, mass and volume we know that
Applying equation 'i' separately to iron and aluminium sphere we get
Equating the masses of iron and aluminium spheres we get
If he pushes the ball it will swing back harder hitting him in the face. if he does not push it the airs force will slow it down to where he will be out of reach of the ball.
Answer:
true
Explanation:
I just had a test on this
Answer:
the period T of whole motion should be twice the value for half at he bottom so T is 0.2sec.
w is angular frequency
formula:2π/T
now k is spring constant
F/R-->mw²
putting values:70*(2π/0.2)²
=4.9x10⁶
so we can say that SHM is not affected by the amplitude of the bounce.
Answer:
force of 279 N
53.75 degrees from east to north
Explanation:
let net force be F , Fn - north force , Fe - east force
let the direction be α angle from east to north