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Lemur [1.5K]
3 years ago
9

A portable DVD player requires six 1.5-volt batteries to operate. If the resistance in the circuit is 7.2 ohms, what is the curr

ent?
A] 0.21 amps
B] 1.3 amps
C] 11 amps
D] 65 amps
E] 1.8 amps
Physics
2 answers:
lara31 [8.8K]3 years ago
6 0
Current = (6*1.5)/7.2= 9/7.2=1.25A=1.3A option B
WINSTONCH [101]3 years ago
5 0

Hello!

A portable DVD player requires six 1.5-volt batteries to operate. If the resistance in the circuit is 7.2 ohms, what is the current?

Data:

We have six 1.5 volt batteries, soon, your tension (V)

V = 1.5 * 6 = 9 Volts

R (resistance) = 7.2 ohms

i (Current intensity) = ? (in Amps)  

Solving (Ohm's First Law):  

i = \dfrac{V}{R}

i = \dfrac{9}{7.2}

\boxed{\boxed{i = 1.25\:amps}}\end{array}}\qquad\checkmark

Note: If we consider the template by approximation, the answer would be:

\boxed{\boxed{\boxed{i\approx 1.3\:amps}}}

Answer:

B] 1.3 amps

____________________________________

I Hope this helps, greetings ... Dexteright02! =)

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a train is moving with an initial velocity of 30 m/s, the brakes are applied so as to produce a uniform acceleration of -1.5 m/s
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Answer:

\boxed{\sf Time \ in \ which \ train \ will \ come \ to \ rest = 20 \ sec}

Given:

Initial velocity (u) = 30 m/s

Final speed (v) = 0 m/s

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Time in which train will come to rest (t).

Explanation:

\sf From \ equation \ of \ motion: \\ \sf \implies \bold{v = u + at} \\ \\ \sf Substituting \ value \ of \ v, \ u \ and \ a:  \\  \sf \implies 0 = 30 + ( - 1.5)(t) \\   \sf  \implies 0 = 30 - 1.5(t) \\  \sf \implies 30 - 1.5(t) = 0 \\  \\  \sf Subtract  \: 30  \: from  \: both  \: sides: \\  \sf \implies (30 -  \boxed{ \sf 30}) - 1.5(t) =  \boxed{ \sf  - 30} \\  \\  \sf 30 - 30 = 0 :  \\  \sf \implies  - 1.5(t) =  - 30 \\  \\  \sf Divide  \: both  \: sides \:  of \:  - 1.5(t) =  - 30 \: by \:  - 1.5 :  \\  \sf \implies  \frac{  - 1.5(t)}{ \boxed{ \sf - 1.5}}  =  \frac{ - 30}{ \boxed{ \sf -1.5 }}  \\  \\  \sf \frac{ \cancel{ \sf 1.5}}{\cancel{ \sf 1.5}}  = 1 :  \\  \sf \implies t =  \frac{ - 30}{ - 1.5}  \\  \\   \sf  \frac{ - 30}{ - 1.5}  =  \frac{\cancel{ \sf 1.5} \times 20}{\cancel{ \sf 1.5}}  = 20 :  \\  \sf  \implies t = 20 \: sec

So,

Time in which train will come to rest = 20 seconds

4 0
3 years ago
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