Answer:
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A force of 43.8 N is required to stretch the spring a distance of 15.5 cm = 0.155 m, so the spring constant <em>k</em> is
43.8 N = <em>k</em> (0.155 m) ==> <em>k</em> = (43.8 N) / (0.155 m) ≈ 283 N/m
The total work done on the spring to stretch it to 15.5 cm from equilibrium is
1/2 (283 N/m) (0.155 m)² ≈ 3.39 J
The total work needed to stretch the spring to 15.5 cm + 10.4 cm = 25.9 cm = 0.259 m from equilibrium would be
1/2 (283 N/m) (0.259 m)² ≈ 9.48 J
Then the additional work needed to stretch the spring 10.4 cm further is the difference, about 6.08 J.
Answer:
g = 11.2 m/s²
Explanation:
First, we will calculate the time period of the pendulum:

where,
T = Time period = ?
t = time taken = 135 s
n = no. of swings in given time = 98
Therefore,

T = 1.38 s
Now, we utilize the second formula for the time period of the simple pendulum, given as follows:

where,
l = length of pendulum = 54 cm = 0.54 m
g = acceleration due to gravity on the planet = ?
Therefore,

<u>g = 11.2 m/s²</u>
Answer:
ask your member
Explanation:
kayo lang din makakasagot nyan
Answer:
R: 27 u
ou 27g/mol
Explanation:
A massa atômica de um elemento é dada pela soma do número atômico (número de protons) com o número de neutrons. Assim:
A= 13+14 = 27