All categories

3 years ago

there were 629,000 women motorcyclists, up from 447,000 eight years ago. what's the percentage of increase?

Mathematics

1 answer:

Mila [183]3 years ago

6 0

This is the formula for percentage increase and decrease

You might be interested in

Use the given graph to determine the limit, if it exists. (4 points) A coordinate graph is shown with an upward sloped line cros

melamori03 [73]

Answer:

65x and 32 that your answer

8 0

3 years ago

Read 2 more answers

Savannah is 24 years older than Ryan, while Sebastian is 5 times as old as Ryan. If Savannah and Sebastian are twins, which equa

Gnom [1K]

Answer:

Kim is 24 years older than Tom Kim and Tom are twins. These two statements are not compatible, unless the mother of Kim and Tom was in labor for 24 years LOL

Second statement

Savannah and Sebastian are the same age (twins)

X being Ryan's age the correct answer is 24+x = 5x

D is the correct answer

To solve 24+x= 5x

Subtract x from each side

24= 4x

Divide each side by 4

6= x

Savannah is 30 Sebastian is 30 Ryan is 6

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
\\
\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0
\\
\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
\\
\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}
\\
\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
\\
\\y' = \frac{3}{( -32 )}$

7 0

3 years ago

Jessica Barth 15 pieces of ribbon each piece of ribbon was 2.25 yards long what is the total amount of ribbon Jessica bu Jessica

Flauer [41]

The answer is 3.375

6 0

3 years ago

A $500 couch is marked up 20%. What is the new price of the couch?

Aleks04 [339]

Pretty sure the answer is $600

Hope this helps

6 0

3 years ago