Answer:
a
Step-by-step explanation:
aa
<span>Assume that,
x^2+4x-5 = 0 .......(1)
Then,
x^2+4x-5 = 0
x^2+5x-1x-5 =0
x(x+5)-1(x+5) = 0
(x+5) (x-1) = 0
We get x=-5 and x=1
Sub x=-5 in equ (1)
(-5)^2+4(5)-5 = 0
-25+20-5 = 0
-25+25= 0
0 = 0
Sub x=1 in equ (1)
(1)^2+4(1)-5 = 0
1+4-5 = 0
5-5 = 0
0 = 0
Therefore x value is -5 and 1</span>
Notice the picture below
now, if the arc "x" is 48°, and the arc across the circle is also 48°, then those chords are congruent, notice the chords in red
Answer:A -3,6
Step-by-step explanation: Substitue the answers in and they work out
V+27=117
Subtract 27 to 117:
v=90