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3 years ago

What is the divisibility factor of 21

Mathematics

1 answer:

tekilochka [14]3 years ago

7 0

21÷7=3 and if you need it 7×3 is 21

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Talulah is an ecologist who studies the change in the penguin population of Antarctica over time. She

blondinia [14]

Answer:

P(t) = 27000 - 4*t

Step-by-step explanation:

Over a period of time, if we know the population at certain time, and the rate of change of the population, we can express the function describing such population by means of these two parameters

Then:

P(t) = P₀ + 4*t

In our case

P(t) = 27000 - 4*t

Sign minus is for decreasing population t is in months, 4 is the rate of change and finally 27000 was population the first time Talulah counted the population

8 0

3 years ago

What is 1x1= 3y128367138 riding it equals to 1

Anon25 [30]

Yes that is extremely accurate

5 0

3 years ago

Read 2 more answers

-0.6 + (- 2.5) <br> can someone tell me and explain please the answer.

xenn [34]

A negative plus a negative is going to be a negative in this case. so your subtracted but to really look like your adding them together

4 0

2 years ago

A rectangle has vertices at (0 0) (3 0) and (0 6). what is the area of the rectangle answer

KonstantinChe [14]

Answer:

18 sq. units

Step-by-step explanation:

Height would be 6 and Length would be 3

6 x 3 = 18

For further help, use a coordinate grid and plot the points

3 0

3 years ago

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Find the domain of the function y = 3 tan(23x)

solmaris [256]

Answer:

$\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

In other words, the $x$ in $f(x) = 3\, \tan(23\, x)$ could be any real number as long as $x \ne \displaystyle \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right)$ for all integer $k$ (including negative integers.)

Step-by-step explanation:

The tangent function $y = \tan(x)$ has a real value for real inputs $x$ as long as the input $x \ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

Hence, the domain of the original tangent function is $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

On the other hand, in the function $f(x) = 3\, \tan(23\, x)$ , the input to the tangent function is replaced with $(23\, x)$ .

The transformed tangent function $\tan(23\, x)$ would have a real value as long as its input $(23\, x)$ ensures that $23\, x\ne \displaystyle k\, \pi + \frac{\pi}{2}$ for all integer $k$ .

In other words, $\tan(23\, x)$ would have a real value as long as $x\ne \displaystyle \frac{1}{23} \, \left(k\, \pi + \frac{\pi}{2}\right)$ .

Accordingly, the domain of $f(x) = 3\, \tan(23\, x)$ would be $\mathbb{R} \backslash \displaystyle \left\lbrace \left. \frac{1}{23}\, \left(k\, \pi + \frac{\pi}{2}\right) \; \right| k \in \mathbb{Z} \right\rbrace$ .

4 0

2 years ago