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iVinArrow [24]
3 years ago
10

What is 3/7 +1/5 and how would I get it​

Mathematics
2 answers:
barxatty [35]3 years ago
7 0

Answer:

22/35

Step-by-step explanation:

1. find a common denominator

- for this you would multiply each of the denominators to each other as well as the numerators.

- (3*5 / 7*5) + (1*7 / 5*7)

2. 15/35 + 7/35 = 22/35

3. The denominator stays the same

Hope this helps :)

Aleks04 [339]3 years ago
5 0

Answer:

22/35

Step-by-step explanation:

3/7 + 1/5

First, find a common denominator.

7*5=35  multiply the numerator by 5 too: 3*5=15

5*7=35  multiply the numerator by 7 too: 1*7=7

15/35 + 7/35

=22/35

Cannot be simplified.

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​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
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The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

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So, from the above eq1 we can find the first root of the polynomial, which will be:

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Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

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