1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Finger [1]
3 years ago
12

Two particles are fixed to an x axis: particle 1 of charge -1.00 x 10-7 C is at the origin and particle 2 of charge +1.00 x 10-7

C is at x = 17.1 cm. Midway between the particles, what is the magnitude of the net electric field?
...?
Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
6 0
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint. 

The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
</span>
Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
You might be interested in
A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature
Anuta_ua [19.1K]

Answer:

a) c = 1/15

b) =2/5

c) = 3/5

d) No, it cannot be the PMF of y.

Step-by-step explanation:

We have that

p_X(x)\geq0

4 0
3 years ago
500(x – 3) = 5,000<br><br> What’s the value of x?
Vladimir79 [104]

Answer:

13

Step-by-step explanation:

500(x-3)=5000

500x-1500=5000

500x=5000+1500

500x=6500  /:500

x=13

4 0
3 years ago
Read 2 more answers
Solve the system or linear equations
Vanyuwa [196]

Answer:

37. {-1, -1}.

Step-by-step explanation:

I'll solve the first one . The other can be solved in a similar way. We can use the method of elimination.

x1 - x2 = 0

3x1 - 2x2 = -1

We can multiply the first equation by -2. We then have an equation containing + 2x2 so when we add this to the second equation the 2x2 will be eliminated

So the first equation becomes:

-2x1 + 2x2 = 0     Bring down the second equation:

3x1 - 2x2 = -1       Now adding, we get:

x1 + 0 = -1

so x1 = -1.

Now we substitute this value of x1 in the original first equation:

-1 - x2 = 0

-1 = x2

x2 = -1.

So the solution set is {-1, -1}.

If there are more than 2 equations you can use a combination of substitutions and eliminations.

8 0
3 years ago
WILL MARK BRAINLIEST!! PLZ HELP!!
olasank [31]

Answer:

The answer is D.

Step-by-step explanation:

When x=0, then y=300, so it has to be more than that.

When x=25, y=300, so it has to be less than that.

8 0
3 years ago
A bag has four balls labeled A, B, C, and D.
denis-greek [22]

Answer:

b

Step-by-step explanation:

7 0
3 years ago
Other questions:
  • Does anyone know how to work this out?
    10·2 answers
  • What are the coordinates of the vertices of the image of
    8·2 answers
  • Are the angles with the given measures complementary, supplementary, or neither?
    11·2 answers
  • A baker knows that the daily demand for mango pies is a random variable that follows the normal distribution with a mean of 45.4
    10·1 answer
  • When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^1.4
    14·1 answer
  • Determine whether the function is proportional or nonproportional. y = 3x -
    10·1 answer
  • Pls help. Take a pic of your work on paper thanks.
    7·2 answers
  • the temperature was 8 degrees at noon. by 11 p.m., it had dropped 12 degrees. How was the temperature at 11 p.m. ​
    13·1 answer
  • PLLLLEASE ASAP GUYS PLEASEE OMG
    11·2 answers
  • On a coordinate plane, a parabola opens up. It goes through (negative 2, 4), has a vertex at (0.25, negative 6), and goes throug
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!