The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C </span> Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Step-by-step explanation: Let’s use the variable ‘x’ as the percent. You need to make an equation and fill in the blanks. ___ is ____% of ____. So 380 is x% of 475. Now solve the problem. 380/475 = x/100, cross multiply. Now you have 475x = 380 * 100 or 475x = 38000. Now divide each side by 475. Now you have, x = 80%. Now you subtract. 100% - 80%. AND YOU GET 20%
If patio is square it means that area of if is where a is one side Now we can substitute A=200 and solve eq a= a=14.1421 Now we are rounding to the nearest tenths a=14.1 because next number is 4 and is less then 5. The result is 14.1
where a is one side
