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wolverine [178]
4 years ago
11

Kevin has $4.85 in nickels and dimes. If he has 34 fewer dimes than nickels, how many coins (nickels and dimes) does he have alt

ogether?
Mathematics
2 answers:
pochemuha4 years ago
4 0
.05n + .10d = 4.85
n - 34 = d
Substitute the second equation into the first equation and solve for n.
.05n + .10(n - 34) = 4.85
.05n + .10n - 3.4 = 4.85
combine like terms
.15n - 3.4 = 4.85
add 3.4 to both sides
.15n = 8.25
divide both sides by .15
n = 55
d = n - 34
d = 55 - 34
d = 21

CHECK
21 * .1 = 2.10
55 * .05 = 2.75
2.10 + 2.75 = 4.85

21 dimes and 55 nickels
NeX [460]4 years ago
3 0

Answer:

Step-by-step explanation:

it would be 76 coins

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Midpoint Formula:
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The coordinates of the midpoint of the segment joining the two points (0, 2) and (6, 4)​ is (3, 3)

<h3><u>Solution:</u></h3>

Given that two points are (0, 2) and (6, 4)​

To find: coordinates of the midpoint of the segment joining the two points

<em><u>The midpoint of line joining two points is given as:</u></em>

For a line containing two points (x_1, y_1) and (x_2, y_2)

\text {Midpoint}(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)

In the given sum, two points are (0, 2) and (6, 4)​

x_{1}=0 ; y_{1}=2 ; x_{2}=6 ; y_{2}=4

Substituting the values in given formula,

\begin{array}{l}{\text {Midpoint}(x, y)=\left(\frac{0+6}{2}, \frac{2+4}{2}\right)} \\\\ {\text {Midpoint }(x, y)=\left(\frac{6}{2}, \frac{6}{2}\right)=(3,3)}\end{array}

Thus the required midpoint is (3, 3)

8 0
3 years ago
"If three angles and two sides of two triangles are congruent, are the triangles congruent? Why or why not?"
Anettt [7]

Answer:

yes

Step-by-step explanation:

because the corresponding angles are congruent, the triangles are congruent through CPCTC. If two sides are congruent and an included angle, then the triangles are congruent through the SAS postulate. And if two sides and a non-included angle are congruent then the triangles are congruent through the AAS postulate. Any way of looking at this proves congruency through various postulates, therefore the trianlges are congruent.

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Angelina_Jolie [31]
I think 18q-4 is the answer
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On a coordinate plane, an image rectangle has points (negative 5, 0), (5, 0), A prime (5, negative 5), (negative 5, negative 5).
aev [14]

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Step-by-step explanation: I did the test ;D

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3 years ago
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You put the same numbers by accident

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