3(x^2 +2xh + h^2) -4(x + h) -5
(3x^2 + 6xh + 3h^2 -4x -4h -5 - ( 3x^2 -4x -5))/h
(6xh + 3h^2 -4h)/h
h(6x +3h - 4)/h
6x + 3h -4
..................................
Answer: x = 7
Explanation:
Subtract 8 from both sides to isolate x.
x + 8 = 15
x + 8 -8 = 15 - 8
x = 15 - 8
x = 7
Solve for x by simplifying both sides of the equation, then isolating the variable.
ANS:
x=0
Answer:
<h2>2¹²</h2>
Step-by-step explanation:
The sum of the coefficients in the expansion of (x+1)^12:
= 12C0 + 12C1 + 12C2 + . . . + 12C11 + 12C12
the formula says that this sum equal to 2¹².
Other examples
The sum of the coefficients in the expansion of (x+1)^3:
3C0+3C1+3C2+3C3
=8 = 2³
The sum of the coefficients in the expansion of (x+1)^4:
4C0+4C1+4C2+4C3+4C4
=16 = 2⁴
:)
