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ratelena [41]
3 years ago
9

Simplify. Write the expression using only positive exponents. 8x^3/2x^9

Mathematics
2 answers:
Helga [31]3 years ago
6 0
4x
4 \frac{1}{ {x}^{6} }
lapo4ka [179]3 years ago
3 0
The original problem is a bit vague in terms of notation.

If you mean (8x^3)/(2x^9), which says "all of '8x^3' over all of '2x^9' ", then you'll do two things

A) Divide the coefficients 8 over 2 to get 8/2 = 4. The final coefficient is 4.

B) Subtract the exponents: (large)-(small) = 9-3 = 6. The 6 is going to be an exponent in the denominator because the larger exponent 9 is in the denominator

-------------------------------

Therefore,
(8x^3)/(2x^9)
simplifies to
4/(x^6)

In other words,
(8x^3)/(2x^9) = 4/(x^6)
is a true equation for any number x as long as the number is not 0.
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Expand and simplify (4+×)(5+×)​
Minchanka [31]
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Hope this helps!
8 0
3 years ago
a group of students organized a car wash to raise money for charity. The students charged 5$ for each car they washed. In 3 hour
saw5 [17]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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What is the equation of a line in slope intercept form that is perpendicular to y=2/3x+2 and passes through the points (-2,2)? H
JulijaS [17]

Answer:

y = -\frac{3}{2}x -1

Step-by-step explanation:

Given

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Required

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First, we need to determine the slope of y = \frac{2}{3}x + 2

An equation is of the form:

y = mx + b

Where

m = slope

In this case:

m = \frac{2}{3}

Next, we determine the slope of the second line.

Since both lines are perpendicular, the second line has a slope of:

m_1 = \frac{-1}{m}

m_1 = \frac{-1}{2/3}

m_1 = -\frac{3}{2}

Since this line passes through (-2,2); The equation is calculated as thus:

y - y_1 = m_1(x - x_1)

Where

(x_1,y_1) = (-2,2)

This gives:

y - 2 = -\frac{3}{2}(x - (-2))

y - 2 = -\frac{3}{2}(x +2)

y - 2 = -\frac{3}{2}x -3

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y - 2+2 = -\frac{3}{2}x -3 + 2

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8 0
3 years ago
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irinina [24]
X+3=6
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4 0
3 years ago
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Norma-Jean [14]

Answer:

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Step-by-step explanation:

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