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Answer:
(a) 4/3
(b) y -3 = 4/3(x -1)
(c) y -3 = -3/4(x -1)
(d) r = 5
Step-by-step explanation:
a) The slope is given by the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (7 -3)/(4 -1) = 4/3
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b) The radius is normal to the circle. The point-slope form of the equation for a line can be useful here:
y -k = m(x -h) . . . . . line with slope m through point (h, k)
For slope 4/3, the line through point (1, 3) will have the equation ...
y -3 = 4/3(x -1) . . . . point-slope equation of the normal
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c) The tangent is perpendicular to the radius. It will have a slope that is the opposite reciprocal of the slope of the radius: -1/(4/3) = -3/4.
y -3 = -3/4(x -1) . . . . point-slope equation of the tangent
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d) The radius can be found from the distance formula.
d = √((x2 -x1)² +(y2 -y1)²)
d = √((4 -1)² +(7 -3)²) = √(3² +4²) = √25 = 5
The radius of the circle is 5.
The equation describes a circle of radius 2 centered at (x, y) = (7, -8). In standard form, the equation would be
.. (x -7)^2 +(y +8)^2 = 4
A graph of it can be seen here. https://www.desmos.com/calculator/14zlfrtoa1
Answer:
The cost of 1 taco = $4
The cost of 1 quesadilla = $7.50
Step-by-step explanation:
Let the cost of tacos be x and the cost of quesadillas be y.
<h3><u>Given condition:</u></h3>
x + 3y = 26.50 ------------------(1)
3x + y = 19.50 -------------------(2)
Multiply Eq. (2) by 3
3(3x + y) = 19.50 * 3
9x + 3y = 58.5 -----------------(3)
Subtract Eq. (3) from (1)
x + 3y - 9x - 3y = 26.50 - 58.50
x - 9x = -32
-8x = -32
8x = 32
Divide 8 to both sides
x = $4
Put x = 4 in (1)
4 + 3y = 26.50
Subtract 4 to both sides
3y = 26.50 - 4
3y = 22.50
Divide 3 to both sides
y = $7.50
So,
The cost of 1 taco = $4
The cost of 1 quesadilla = $7.50
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