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vova2212 [387]
3 years ago
10

a piece of thread is 11/12 inches long. Jill needs to cut the thread into 1/6 segments how many segments can she cut?​

Mathematics
1 answer:
zubka84 [21]3 years ago
5 0
Jill can cut 5.5 segments from the amount of thread she has.
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Help me!!! PLEASE (I only have 13 points)
yan [13]

Answer:

<em>0.6 ÷ 0.3 - Option 2.</em>

<em>0.2 × 0.9 - Option 3.</em>

3 0
2 years ago
When dividing the polynomial using synthetic division, which of the following setup boxes would be used?
Galina-37 [17]

The setup boxes in the synthetic division are (b)

<h3>How to determine the setup boxes?</h3>

The dividend is given as:

x^3 + 4x^2 + x - 6

The divisor is given as:

x - 2

Set the divisor to 0

x - 2 = 0

Solve for x

x = 2

Remove the variables in the dividend

1 + 4 + 1 - 6

Remove the arithmetic signs

1  4  1 - 6

So, the setup is:

2 | 1  4  1 - 6

Hence, the setup boxes are (b)

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8 0
1 year ago
Please respond quickly
storchak [24]
A should be the right answer. Hope this helped!
6 0
2 years ago
Read 2 more answers
An isosceles triangle has two sides of equal length, a, and a base, b. The perimeter of the triangle is 15.7 inches, so the equa
Stella [2.4K]

Answer:

Please inform me if I am wrong

7 0
3 years ago
What is the volume of a hemisphere with a radius of 26.7 m, rounded to the nearest tenth of a cubic meter?
attashe74 [19]

Answer:

39,865.1m^3

Step-by-step explanation:

a hemisphere is half a sphere.

And if the formula for the volume of a sphere is:

V=\frac{4\pi r^3}{3}

we must calculate the volume of the sphere and in the end divide by two to find the volume of the hemisphere.

Since the radius is:

r=26.7m

substituting this into the formula for volume:

V=\frac{4\pi (26.7m)^3}{3} \\\\V=\frac{4(3.1416)(19,034.163m^3)}{3} \\\\V=79,730.12m^3

this is the volume of the total sphere, thus the volume of a hemisphere is:

\frac{V}{2}=\frac{79,730.12m^3}{2}\\  =39,865.06m^3

rounding to the nearest tenth:

39,865.1m^3

8 0
3 years ago
Read 2 more answers
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