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Artyom0805 [142]
3 years ago
7

Nehdudhdhddjjdhdjdjdjr

Mathematics
2 answers:
Anarel [89]3 years ago
8 0
Hey njjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj
ludmilkaskok [199]3 years ago
7 0
1.
A= 90-34 = 56
2.
A=180-157=23
3.
Acute triangle
4.
I can’t see
5.
Acute
Obtuse
Right triangle

Hope this help
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Use the binomial series to expand the function as a power series 3/((6+x)^3)
Bingel [31]
I know bionomial theorem
pascal's triangle would be eseir though

pascal's triangle
1              0
1 1            1
1 2 1        2
1 3 3 1       3
1 4 6 4 1    4

those are the coefieicnets
in (a+b)^3
1a^3+3a^2b+3ab^2+1b^3 so

(6+x)^3=6^3+3(6^2)x+3(6)x^2+1x^3=

and this is all under 3
\frac{3}{216+108x+18x^{2}+x^{3}}

6 0
3 years ago
MY NO<br> (a) When we multiply two powers with the same base, we The exponents
gizmo_the_mogwai [7]

Answer:

add the exponents

Step-by-step explanation:

when multiplying 2 powers that have the same base, you can add the exponents

3 0
3 years ago
EASY PROBABILITY<br> What did I do wrong?
Katen [24]

Answer:

You put 19 instead of 3:)

Step-by-step explanation:

8 0
3 years ago
What are the exact values of sin(2π3radians) and cos(2π3radians)
topjm [15]
We know that
2π/3 radians-------> convert to degrees-----> 2*180/3---> 120°
120°=90°+30°

Part a) Find <span>sin(2π/3)
</span>sin(2π/3)=sin (90°+30°)
we know that
sin (A+B)=sin A*cos B+cos A*sin B
so
sin (90°+30°)=sin 90*cos 30+cos 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
sin (90°+30°)=1*√3/2+0*1/2-----> √3/2

the answer part a) is
sin(2π/3)=√3/2

Part b) Find cos (2π/3)
cos (2π/3)=cos (90°+30°)
we know that
cos (A+B)=cos A*cos B-sin A*sin B
so
cos (90°+30°)=cos 90*cos 30-sin 90*sin 30
sin 90=1
cos 30=√3/2
cos 90=0
sin 30=1/2
cos (90°+30°)=0*√3/2-1*1/2----> -1/2

the answer part b) is
cos (2π/3)=-1/2


4 0
3 years ago
Please I really need help with these
MrRissso [65]

Answer:

Idk lol

Step-by-step explanation:

8 0
4 years ago
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