Step-by-step explanation:
You can solve systems of equations using either substitution or elimination. For these problems, I recommend elimination. I'll do the first one as an example.
-3x + 16y = 9
-4x + 8y = 12
Multiply the second equation by -2.
8x − 16y = -24
Add to the first equation (notice the y's cancel out).
(-3x + 16y) + (8x − 16y) = 9 − 24
5x = -15
Solve for x.
x = -3
Now you can plug this into either equation to find y.
-3(-3) + 16y = 9
9 + 16y = 9
y = 0
The solution is (-3, 0).
1/2-1/4
(1/2x2)-1/4
2/4-1/4
2-1
1
1/4
Hello!
This is a problem about the general solution of a differential equation.
What we can first do here is separate the variables so that we have the same variable for each side (ex. 
with the 
term and 
with the 
term).
Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.
Then here, we just solve for and we have our general solution.
![y=\sqrt[3]{\frac{1}{2}x^2-x+C}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B2%7Dx%5E2-x%2BC%7D)
We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.
Hope this helps!
Answer:
a.)48
b.)528
c.)448
Step-by-step explanation:
a.)8x8=64. 4x4=16 64-16=48
b.)48(from a. answer)x11=528
c.)11x8(x2 for the other side)=176. 11x4x4=176.
48x2=96. 176+176+96=448
