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3 years ago

Enter an inequality that represents the graph in the box.

Mathematics

1 answer:

sergejj [24]3 years ago

5 0

Answer:

(0,6)-(2,0)

Step-by-step explanation:

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NEED HELP ASAP PLEASE! BRAINLIEST TO RIGHT ANSWER! For two similar triangles ABC and DEF, the scale factor of ∆ABC to ∆DEF is 2

hram777 [196]

Answer:

Assuming the similarity is that BC scales to EF, answer is

D. 1.5BC

Step-by-step explanation:

Because the triangles are smilar, AB/BC = DE/EF

If AB = 2BC

then DE = 2EF

but also DE = 3BC

so 2EF = 3BC

EF = 1.5BC

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3 years ago

what is the coefficient of x^2y^3 in the expansion of (2x+y)^5? A. 2 B. 5 C. 40 D. 80 E. it does not exist

VashaNatasha [74]

It doesn't make sense

8 0

3 years ago

Select the two values of x that are roots of this equation.<br> X2 + 2x - 5 = 0

LenaWriter [7]

Answer:

$x=-1+\sqrt{6 }$

$x=-1-\sqrt{6 }$

Step-by-step explanation:

$x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

Ignore the A before the ±. It wouldn't let me type it correctly.

x² + 2x - 5 = 0

a = 1

b = 2

c = - 5

$x=\frac{-2±\sqrt{2^{2}-4((1)(-5)) } }{2(1)}$

$x=\frac{-2±\sqrt{4-4((1)(-5)) } }{2(1)}$

$x=\frac{-2±\sqrt{4+20 } }{2(1)}$

$x=\frac{-2±\sqrt{24 } }{2}$

$x=\frac{-2±\sqrt{(2)(12) } }{2}$

$x=\frac{-2±\sqrt{(2)(2)(6) } }{2}$

$x=\frac{-2±\sqrt{(2)(2)(2)(3) } }{2}$

$x=\frac{-2±(\sqrt{2} )(\sqrt{2})(\sqrt{(2)(3) )} }{2}$

$x=\frac{-2±2\sqrt{6 } }{2}$

Two separate equations

$x=\frac{-2+2\sqrt{6 } }{2}$

$x=\frac{-2-2\sqrt{6 } }{2}$

$x=-1+\sqrt{6 }$

$x=-1-\sqrt{6 }$

7 0

3 years ago

This is from IXL and need help on it please...

8_murik_8 [283]

Answer:

∠1 and ∠2

angles on a straight line add up to 180

6 0

3 years ago

Read 2 more answers

PLEASE HELP PLEASE HELP

il63 [147K]

1 to 4

4 / 4 = 1

16 / 4 = 4

8 0

2 years ago