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NNADVOKAT [17]
3 years ago
14

HEY YOU, YES YOU, PLEASE HELP ME ASAP!!

Mathematics
1 answer:
damaskus [11]3 years ago
8 0
(-3,0) is your answer
Pls mark brainliest
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What is the area of a square 11cm and 15cm
Veronika [31]
To find the area you times length times width give you the area so 11 X 15 is 165cm squered
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4 years ago
Find the distance between the points (-3,6)and(-3,-7)
elena-14-01-66 [18.8K]

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13 this needed to be 20 characters long just ignore

Step-by-step explanation:

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3 0
3 years ago
There are eight marbles in a bag. Four marbles are blue (B), two marbles are red (R) and two marbles are green (G) Steve takes a
inna [77]

Answer:

1/2

Step-by-step explanation:

4 of the 8 marbles are blue:

4/8 = 1/2

3 0
4 years ago
An equation for the depreciation of a car is given by y=A(1-r)t where y=current value of the car.A=original cost r=rate of depre
Ann [662]
<h3>Answer: Approximately 6.58 years old</h3>

The more accurate value is 6.57881347896059, which you can round however you need. I picked two decimal places.

==================================================

Explanation:

Let's pick a starting value of the car. It doesn't matter what the starting value, but it might help make the problem easier. Let's say A = 1000. Half of that is 1000/2 = 500.

So we want to find out how long it takes for the car's value to go from $1000 to $500 if it depreciates 10% per year.

The value of r is r = 0.10 as its the decimal form of 10%

t is the unknown number of years we want to solve for

---------------------------

y = A(1 - r)^t

500 = 1000(1 - 0.1)^t

500 = 1000(0.9)^t

1000(0.9)^t = 500

0.9^t = 500/1000

0.9^t = 0.5

log( 0.9^t ) = log( 0.5 )

t*log( 0.9 ) = log( 0.5 )

t = log( 0.5 )/log( 0.9 )

t = 6.57881347896059

Note the use of logs to help us isolate the exponent.

6 0
3 years ago
Solve the following system of equations and show all work. y = x^2 + 3 y = x + 5 (10 points)
svetoff [14.1K]

Answer:

(- 1, 4 ) and (2, 7 )

Step-by-step explanation:

Given the 2 equations

y = x² + 3 → (1)

y = x + 5 → (2)

Substitute y = x² + 3 into (2)

x² + 3 = x + 5 ← subtract x + 5 from both sides

x² - x - 2 = 0 ← in standard form

(x - 2)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2

x + 1 = 0 ⇒ x = - 1

Substitute these values into (2) for corresponding values of y

x = 2 : y = 2 + 5 = 7 ⇒ (2, 7 )

x = - 1 : y = - 1 + 5 = 4 ⇒ (- 1, 4 )

4 0
4 years ago
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