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N76 [4]
3 years ago
5

Please answer this Square and Square Root question (at least one)

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0
H. 100=10squared and 64=8squared 25=5squared
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In △PKQ, PK = KQ = 12, m∠P = 35º. Find PQ.
Neporo4naja [7]

The length of PQ is 19.66 units

Step-by-step explanation:

The given is:

1. PK = KQ = 12

2. m∠P = 35º

We need to find the length pf PQ

∵ PK = KQ

∴ m∠P = m∠Q

∵ m∠P = 35°

∴ m∠Q = 35°

The sum of measures of the angles of a triangle is 180°

∴ m∠P + m∠Q + m∠K = 180°

∴ 35 + 35 + m∠K = 180

∴ 70 + m∠K = 180

- Subtract 70 from both sides

∴ m∠K = 110°

Let us use cosine rule to find the length of PQ

∵ PQ = \sqrt{(KP)^{2}+(KQ)^{2}-2(KP)(KQ)cos(K)}

∵ PK = 12 , KQ = 12 , m∠K = 110°

- Substitute these values in the rule

∴ PQ = \sqrt{(12)^{2}+(12)^{2}-2(12)(12)cos(110)}

∴ PQ = 19.66

The length of PQ is 19.66 units

Learn more:

You can learn more about triangle in brainly.com/question/12985572

#LearnwithBrainly

4 0
3 years ago
line J passes through points (-6,1) and (-3,6) . Line m is parallel to line j and passes through point (15,-1).what is the equat
VMariaS [17]
Slope of the line J
(6-1) / (-3-(-6))
5 / 3

so
m = 5/3

If this line passes through (15,-1)
y = mx + c
-1 = (5/3)*15 + c
-1 = 25 + c
c = -26

equation is
y = (5/3)x - 26
7 0
3 years ago
Choose the correct slope of the line that passes through the points (1, −3) and (3, −5).
Flura [38]
Slope of a line passing though point (x1,y1) nd (x2,y2) is
(y2-y1)/(x2-x1)

we have
(1,-3) and (3,-5)
x1=1
y1=-3
x2=3
y2=-5

slope=(-5-(-3))/(3-1)=(-5+3)/(2)=-2/2=-1

slope=-1
4 0
3 years ago
Read 2 more answers
The product of 4x and 0 is:<br> 4x<br> 4<br> 0
ki77a [65]

Answer: <em>0</em>

Step-by-step explanation:

<em>Simply the answer is </em><em>0</em><em> because anything multiplied by </em><em>0</em><em> will result in </em><em>0</em>

<em>4x(0) =</em><em> 0 </em>

7 0
3 years ago
Write the equation 2x-3y=6in slope -intercept form​
Tcecarenko [31]

Answer:

y = 2/3 x -2

Step-by-step explanation:

Slope intercept form is y = mx+b where m is the slope and b is the y intercept

We need to solve for y

2x-3y = 6

Subtract 2x from each side

2x-2x-3y=-2x+6

-3y = -2x+6

Divide  by -3

-3y/-3 = -2/-3x+6 /-3

y = 2/3 x -2

The slope is 2/3 and the y intercept is -2

7 0
2 years ago
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