Wbt do i multiply 7 by to get 21 or the first number they both have the same?

VladimirAG [237]

Hello there.

How to solve 6x-3=7x-11
6x−3=7x−11
6x−3−7x=7x−11−7x−x−3=−11
−x−3+3=−11+3−x=−8
−x/−1=−8/−1x=8
Answer: 8

6 0

3 years ago

Han creates a scatter plot that displays the relationship between the number of items sold, x, and the total revenue, y, in doll

masya89 [10]

Answer:

In context of the problem, -40 means that 40 was the difference between the actual data, and the estimated data.

Step-by-step explanation:

5 0

3 years ago

Resolve into partial fractions 7-5x/2x^2+x-1

Flauer [41]

The decomposition of partial fractions is to start with the simplified reply and then take it apart, to "decompose" the final expression into its initial polynomial fractions.

Given:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\$

To find:

partial fractions=?

Solution:

$\to \bold{\frac{7-5x}{2x^2+x-1}}\\\\\to \bold{\frac{7-5x}{2x^2+x(2-1)-1}}\\\\\to \bold{\frac{7-5x}{2x^2+2x-x-1}}\\\\\to \bold{\frac{7-5x}{2x(x+1)-1(x+1)}}\\\\\to \bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{A}{(2x-1)} - \frac{B}{(x+1)} }\\\\\to \bold{7-5x = \frac{A ((2x-1)(x+1))}{(2x-1)} - \frac{B((2x-1)(x+1))}{(x+1)} }\\\\\to \bold{7-5x = A(x+1) -B(2x-1) }\\\\$

putting $x=-1$

$\to \bold{7-5(-1) = A(-1+1) -B(2(-1)-1) }\\\\\to \bold{7+5 = A(0) -B(-2-1) }\\\\\to \bold{12 = +3B }\\\\\to \bold{B = \frac{12}{3} }\\\\\to \bold{B = 4 }\\\\$

putting $x= \frac{1}{2}$

$\to \bold{7-5(\frac{1}{2}) = A(\frac{1}{2}+1) -B(2(\frac{1}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B((\frac{2}{2})-1) }\\\\\to \bold{7-\frac{5}{2} = A(\frac{3}{2}) -B(1-1) }\\\\\to \bold{\frac{14-5}{2} = A(\frac{3}{2}) -B(0) }\\\\\to \bold{\frac{9}{2} = A(\frac{3}{2})}\\\\\to \bold{\frac{9}{2} \times \frac{2}{3} = A}\\\\\to \bold{\frac{9}{3} = A}\\\\\to \bold{A=3}\\\\$

So, the final answer is " $\bold{\frac{7-5x}{(2x-1)(x+1)} = \frac{3}{(2x-1)} - \frac{4}{(x+1)} }\\\\$ ".

Learn more:

brainly.com/question/22286068

3 0

3 years ago

In one baseball season, Peter hit twice the difference of the number of home runs Alice hit and 6. Altogether, they hit 18 home

shutvik [7]

H = Alice's home runs
p = Peter's home runs

p = 2(h - 6)
p + h = 18

Simplified:
p = 2h - 12
p - 2h = -12

p + h = 18

Solve simultaneously:
p - 2h = -12 ...1
p + h = 18 ...2

1 - 2:
-3h = - 30
h = -30/-3
h = 10

Substitute into 2:
p + h = 18
p + 10 = 18
p = 18 - 10
p = 8

Therefore, Peter hit 8 home runs and Alice hit 10 homeruns.

6 0

3 years ago

Part A

Mkey [24]

Answer:

4 1/2

Step-by-step explanation:

4 1/2

3 0

3 years ago

Read 2 more answers