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3 years ago

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Mathematics

1 answer:

pishuonlain [190]3 years ago

5 0

Ummmmm huh? Ok, whatever

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Which expression is equivalent to the given expression? Assume the denominator does not equal zero.

bulgar [2K]

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For these type of problems download photo math
It’ll be faster than here with steps!

8 0

2 years ago

The two lines y= 6x+15 and y= mx+4 intersect at x= -2. What is the y-coordinate of their intersection point

taurus [48]

Answer:

The y-coordinate of their intersection point is 3

That is y=3

Step-by-step explanation:

Given two lines are y=6x+15 and y=mx+4

Given that the two lines intersect at x=-2

To find the y coordinate of their intersection point :

Equating the two lines

6x+15=mx+4

6x+15-mx-4=0

6x-mx+11=0

(6-m)x+11=0

At x=-2 (6-m)x+11=0

(6-m)(-2)+11=0

(6-m)(-2)=-11

$6-m=\frac{11}{2}$

$-m=\frac{11}{2}-6$

$-m=\frac{11-12}{2}$

$-m=\frac{-1}{2}$

$m=\frac{1}{2}$

Substitute the value $m=\frac{1}{2}$ in y=mx+4 we get

$y=\frac{1}{2}x+4$

At x=-2 $y=\frac{1}{2}(-2)+4$

$=-1+4$

$=3$

Therefore y=3

Therefore the y-coordinate of their intersection point is 3

7 0

3 years ago

if x is the first, or smallest, of three consecutive integers, express the sum of the integer and the third integer as an algebr

Scrat [10]

Consecutive numbers differ by one. So, if $x$ is the first, the three numbers are

$x,\ x+1,\ x+2$

The sum of the first and third integer is

$x+(x+2)=2x+2$

5 0

3 years ago

The diagram shows a circle inscribed in a square.

beks73 [17]

Answer:

Step-by-step explanation:

first lets find the area of the square

A=l*w

12*12=144 m^2

then lets find the are of the circle

A=pi*r^2

A=3.14*(d/2)^2

the diameter of the circle is 12m

A=3.14*(12/2)^2

A=3.14*(6)^2

A=3.14*36

A=113.04 m^2

Now, lets subtract the area of the circle form the area of the square

144-113.04= 30.96 m^2

So, the answer is A

5 0

3 years ago

The coordinates of DEF are D(3,4), E(6,4), and F(5,9). If you translate DEF 3 units left and 2 units up, what are the coordinate

grigory [225]

EXPLANATION:

1.We must locate the points that the exercise gives us in the Cartesian plane.

2.The figure that it gives us must be moved 3 units to the left and then 2 units up.

3.To correctly translate a figure, we must add the units that the exercise indicates and towards the correct direction, if it tells us that to the left is towards the negative axis, then each of the points given in the exercise we will transfer 3 units towards the left and then add each of the points two units up, then we see that the triangle takes new coordinates for the points.

4.The new coordinates for point E are (3,6)

7 0

11 months ago