D. y = 3x + 2
Check (-4, -10)
-10 = 3(-4) + 2
-10 = -12 + 2
-10 = -10 :)
Check (-3, -7)
-7 = 3(-3) + 2
-7 = -9 + 2
-7 = -7 :)
Check (-2, -4)
-4 = 3(-2) + 2
-4 = -6 + 2
-4 = -4 :)
Check (-1, -1)
-1 = 3(-1) + 2
-1 = -3 + 2
-1 = -1 :)
Check (0, 2)
2 = 3(0) + 2
2 = 0 + 2
2 = 2 :)
Right angle
Te reason being is that it has a 90° corner.
Hoped this helped
I think it is the first one: Different bar widths.
Answer:
D.
Step-by-step explanation:
Hi there! You’re correct.
Twice the difference of nine and a number squared would look like

I hope this helped! :)
Answer:
The proof is given below.
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE