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Naya [18.7K]
3 years ago
6

Elizabeth had 10 stamps. She decided to write letters to some of her relatives. After she sent her letters, she had 6 stamps lef

t. How many letters did she mail? A. 10 - 4 = 6 B. 60 6 = 10 C. 6 + 10 = 16 D. 10 - 6 = 4
Mathematics
2 answers:
34kurt3 years ago
8 0
The answer is A. Elizabeth had 10 stamps. The question says after she sent her relatives letters, she had 6 left. 10-6=4 
FromTheMoon [43]3 years ago
6 0
A, she started with 10 and had six left. 10-4=6
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Murrr4er [49]

Taking a quotient, we will see that she can make 7 bowls of cereal (and some leftover milk).

<h3>How many bowls of cereal would kathy have?</h3>

We know that for each bowl, she needs 1/2 cups of milk.

And we also know that she has a total of (3 + 3/5) cups of milk.

To know how many bowls she can make, we need to take the quotient between the total that she has and the amount that she needs for each bowl:

(3 + 3/5)/(1/2)

We can rewrite the total as:

3 + 3/5 = 15/5 + 3/5 = 18/5

Then the quotient becomes:

(18/5)/(1/2) = (18/5)*2 = 36/5 = 35/5 + 1/5 = 7 + 1/5

So she can make 7 bowls of cereal (and some leftover milk).

If you want to learn more about quotients:

brainly.com/question/629998

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6 0
1 year ago
Need help asap please!!!
Alona [7]

Answer:

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Step-by-step explanation:

The coordinates of the point is -2,2 so you subtract 4 and 6. That is -6.-4

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3 years ago
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REY [17]

Answer:  

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When you make a fraction like this in words, all you have to do is Take the number put it on top and the worded number on the bottom. Unless directed otherwise.

5 0
3 years ago
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geniusboy [140]

Answer:

A

Step-by-step explanation:

\frac{4}{5} + \frac{2}{5} = \frac{6}{5} \\Simple make it improper, resulting in answer A

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4 0
2 years ago
3x^2(x^3-1)+2x^3(2x^2+2) <br> Whats the simplified answer?
ahrayia [7]

Answer:

\large\boxed{7x^5+4x^3-3x^2}

Step-by-step explanation:

3x^2(x^3-1)+2x^3(2x^2+2)\qquad\text{use the distributive property:}\ a(b+c)=ab+ac\\\\=(3x^2)(x^3)+(3x^2)(-1)+(2x^3)(2x^2)+(2x^3)(2)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=3x^{2+3}-3x^2+4x^{3+2}+4x^3\\\\=3x^5-3x^2+4x^5+4x^3\qquad\text{combine like terms}\\\\=(3x^5+4x^5)-3x^2+4x^3\\\\=7x^5+4x^3-3x^2

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