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Alecsey [184]
3 years ago
5

Find the local and global extrema for the graph of ƒ(x) = x(25 – x).

Mathematics
1 answer:
Allisa [31]3 years ago
4 0

fx=25x-x²

dy/dx=0

25-2X=0

(=)X=14,5

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(Explanation)

Step-by-step explanation:

Part A:

The graph of y = x^{2} + 2 will be translated 2 units up from the graph of y = x^{2}.

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This is what graph A should look like:

[Attached File]

Part B:

The graph of y = x^{2} - 2 will be translated 2 units down from the graph of y = x^{2}.

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This is what graph B should look like:

[Attached File]

Part C:

The graph of y = 2x^{2} is a stretched version of the graph y = x^{2}. Numbers that are greater than 1 stretch and open up and numbers less than -1 stretch and open down.

This is what graph C should look like:

[Attached File]

Part D:

The graph of y = \frac{1}{2}x^{2} is a compressed version of the graph y = x^{2}. Numbers that are in-between 0 and 1, and -1 and 0 are compressed.

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[Attached File]

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