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Shtirlitz [24]
3 years ago
5

.....................................

Advanced Placement (AP)
2 answers:
ch4aika [34]3 years ago
8 0
I’m not sure what this is but thank you for the free point lol
grandymaker [24]3 years ago
5 0

Answer:

yes that is correct good job

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The ________ division of the geologic time scale is an era of the phanerozoic eon.
4vir4ik [10]
The Proterozoic division of the geological time scale is an era of the Phanerozoic eon. The Proterozoic division began 2.5 billion years ago and ended 542.0 million years ago.
5 0
3 years ago
What is the answer to this math problem with full work advanced geometry
Alisiya [41]

Answer:

Chord UV = 5

Explanation:

Recall that Theorem of congruent chords relating to their arcs states that the intercepted arcs of two chords are congruent if the two chords are of the same length.

The converse of this theorem states that if two intercepted arcs of two corresponding chords are congruent, then the two chords are congruent to each other.

Let's apply the converse of this theorem to the problem given.

We are given that the intercepted arcs of chord UV and chord UT are 34° each.

Therefore, chord UV must be congruent to chord UT.

Since chord UT = 5

Therefore, chord UV = 5

6 0
3 years ago
Need help only on #42!
antiseptic1488 [7]

Answer:

do u still need help

Explanation:

8 0
2 years ago
Which of the following outcomes is most consistent with the pluralist model of democracy?
lana [24]

Answer: d) Federal bureaucrats delay implementation of the new law after it has passed Congress.

Explanation:

The pluralist democracy can be described as a kind of political system where there is more than one center of power. This means that the power is allocated in different hands and authorities. This allows the freedom of association. It may exists without democracy.

The congress has passed the law under its authority but it has to be passed or implemented by the federal bureaucrats as the power is allocated to the different centers under the pluralist model of democracy.

5 0
2 years ago
Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th
lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2

Finding the boundaries of the function gives;

0\times e^{4-0^2} = 0 and 2\times e^{4-2^2} = 2

At t = 1, we have 1\times e^{4-1^2} = e^{3} = 20.086

We find the maximum point as follows;

\frac{\mathrm{d} \left (t\times e^{4-t^2}   \right )}{\mathrm{d} x}=0

From which we have;

\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0

e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0

e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\

e^{4-t^2}=0 or (1 - 2\times t^2 })=0

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for  0 ≤ t ≤ 0  1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

8 0
3 years ago
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