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docker41 [41]
4 years ago
13

In a random sample of 97 women at a company, the mean salary is $45,902 with a standard deviation of $3865. In a random sample o

f 75 men at the company, the mean salary is $48,454 with a standard deviation of $6677. Which interval is the 95% confidence interval for the difference between the mean salaries of all women and men at the company?
A) ($1133.20, $3970.80)
B) ($856.36, $4247.64)
C) ($1686.88, $3417.12)
D) ($319.99, $4784.01)
Mathematics
1 answer:
Delicious77 [7]4 years ago
8 0

Answer:

c

Step-by-step explanation:


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For each direct variation find the constant of variation then find the value of Y when X equals -0.5. Y equals 2 when X equals 3
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For direct variation y varies directly with x, then we use equation y = kx

Where k is the constant of proportionality

Given: Y equals 2 when X equals 3

We plug in 3 for x  and 2 for y and solve for k

y = kx

2 = k(3)

Divide both sides by 3

\frac{2}{3} =k

Now we plug in 2/3 for k  

y=\frac{2}{3}x

Given x=-0.5  and find out y

y=\frac{2}{3}(-0.5)

y=-0.33

the value of y is -0.33 when x=-0.5


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Answer:

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Step-by-step explanation:

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