is in quadrant I, so
.
is in quadrant II, so
.
Recall that for any angle
,

Then with the conditions determined above, we get

and

Now recall the compound angle formulas:




as well as the definition of tangent:

Then
1. 
2. 
3. 
4. 
5. 
6. 
7. A bit more work required here. Recall the half-angle identities:



Because
is in quadrant II, we know that
is in quadrant I. Specifically, we know
, so
. In this quadrant, we have
, so

8. 
Answer:
the answer would be -2, -6 and if you need more help i believe you can work up to it
Step-by-step explanation:
Answer:NIce
Step-by-step explanation:
Answer:
a) Depth changing rate of change is
, When the water is 6 meters deep
b) The width of the top of the water is changing at a rate of
, When the water is 6 meters deep
Step-by-step explanation:
As we can see in the attachment part II, there are similar triangles, so we have the following relation between them
, then
.
a) As we have that volume is
, then
, so we can derivate it
due to the chain rule, then we clean this expression for
and compute with the knowns
, is the depth changing rate of change when the water is 6 meters deep.
b) As the width of the top is
, we can derivate it and obtain
The width of the top of the water is changing, When the water is 6 meters deep at this rate
Y=15+5g
Y is the total cost in one month. 15 is the cost of the membership and 5 is the amount you paid to see the game. G is the variable for the amount of games. You multiple the g by 5 to get the total cost of games per a month that you went and saw. Than you add the base cost of 15 or your starting point. And you get your total cost.