The balance of a shop owner’s bank account is
2 answers:
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Answer/Step-by-sep explanation:
To determine whether the lines given in each box are parallel, perpendicular, or neither, take the following simple steps:
1. Ensure the equations for both lines being compared are in the slope-intercept form, y = mx + b. Where m is the slope.
2. If both lines have the same slope value, m, then both lines are parallel.
3. If the slope of one line is the negative reciprocal of the other, then both lines are perpendicular. That is, x = -1/x.
4. If the slope of both lines are not the same, nor the negative reciprocal of each other, then they are neither parallel nor perpendicular.
1. y = 3x - 7 and y = 3x + 1.
Both have the same slope value of 3. Therefore, they are parallel.
2. ⬜ and
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -⅖ and the slope of the other is ⅖. Therefore, they are neither parallel nor perpendicular.⬜
3. and
The slope of the first line, ¼, is the negative reciprocal of the slope of the second line, 4.
Therefore, they are perdendicular.
4. 2x + 7y = 28 and 7x - 2y = 4.
Rewrite both equations in the slope-intercept form, y = mx + b.
2x + 7y = 28
7y = -2x + 28
y = -2x/7 + 28/7
y = -²/7 + 4
And
7x - 2y = 4
-2y = -7x + 4
y = -7x/-2 + 4/-2
y = ⁷/2x - 2
The slope of the first line, -²/7, is the negative reciprocal of the slope of the second line, ⁷/2.
Therefore, they are perdendicular.
5.⬜ y = -5x + 1 and x - 5y = 30.
Rewrite the second line equation in the slope-intercept form.
x - 5y = 30
-5y = -x + 30
y = -2x/-5 + 30/-5
y = ⅖x - 6
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -5 and the slope of the other is ⅖. therefore, they are neither parallel nor perpendicular.⬜
6.⬜ 3x + 2y = 8 and 2x + 3y = -12.
Rewrite both line equations in the slope-intercept form.
3x + 2y = 8
2y = -3x + 8
y = -3x/2 + 8/2
y = -³/2x + 4
And
2x + 3y = -12
3y = -2x -12
y = -2x/3 - 12/3
y = -⅔x - 4
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -³/2 and the slope of the other is -⅔ therefore, they are neither parallel nor perpendicular.⬜
7. y = -4x - 1 and 8x + 2y = 14.
Rewrite the equation of the second line in the slope-intercept form.
8x + 2y = 14
2y = -8x + 14
y = -8x/2 + 14/2
y = -4x + 7
Both have the same slope value of -4. Therefore, they are parallel.
8.⬜ x + y = 7 and x - y = 9.
Rewrite the equation of both lines in the slope-intercept form.
x + y = 7
y = -x + 7
And
x - y = 9
-y = -x + 9
y = -x/-1 + 9/-1
y = x - 9
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -1, and the slope of the other is 1, therefore, they are neither parallel nor perpendicular.⬜
9. y = ⅓x + 9 And x - 3y = 3
Rewrite the equation of the second line.
x - 3y = 3
-3y = -x + 3
y = -x/-3 + 3/-3
y = ⅓x - 1
Both have the same slope value of ⅓. Therefore, they are parallel.
10.⬜ 4x + 9y = 18 and y = 4x + 9
Rewrite the equation of the first line.
4x + 9y = 18
9y = -4x + 18
y = -4x/9 + 18/9
y = -⁴/9x + 2
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is -⁴/9, and the slope of the other is 4, therefore, they are neither parallel nor perpendicular.⬜
11.⬜ 5x - 10y = 20 and y = -2x + 6
Rewrite the equation of the first line.
5x - 10y = 20
-10y = -5x + 20
y = -5x/-10 + 20/-10
y = ²/5x - 2
The slope of both lines are not the same, nor is the slope of one the negative reciprocal of the other. The slope of one is ⅖, and the slope of the other is -2, therefore, they are neither parallel nor perpendicular.⬜
12. -9x + 12y = 24 and y = ¾x - 5
Rewrite the equation of the first line.
-9x + 12y = 24
12y = 9x + 24
y = 9x/12 + 24/12
y = ¾x + 2
Both have the same slope value of ¾. Therefore, they are parallel.
Answer:
- quadratic function
- y-intercept: y = -6
- x-intercepts: x = 2 and x = 6
- y = 2, x = 4
- y ≥ 0
Step-by-step explanation:
The given graph is a <u>parabola</u> and so it a quadratic function.
The y-intercept is the point at which the curve <u>crosses the y-axis</u>.
From inspection of the graph, this is when y = -6.
The x-intercepts are the points at which the curve <u>crosses the x-axis</u>.
From inspection of the graph, the x-intercepts are x = 2 and x = 6.
The vertex is the <u>turning point</u> of the graph, so the <u>minimum point</u> of a parabola that opens <u>upwards</u>, and the <u>maximum</u> point of a parabola that opens <u>downwards</u>.
From inspection of the graph, the vertex is at (4, 2), so the greatest value of y is y = 2, and it occurs when x = 4.
The curve is <u>above the x-axis</u> between the interval x = 2 and x = 6.
Therefore, the function value is equal to zero or <u>positive</u> in this interval.
So the function value in the given interval is y ≥ 0.
