Answer:
x = 2 ± √11 (I believe)
Step-by-step explanation:
Answer:
Given:
Sham: n= 20, x=0.44, s=1.24,
Magnet:n= 20, x =0.49, s= 0.95
For Sham:
Sample size, n = 20
Sample mean = 0.44
Standard deviation = 1.24
For Magnet:
Sample size = 20
Sample mean = 0.49
Standard deviation = 0.95
The null and alternative hypotheses:
H0: s1²=s2²
H1: s1² ≠ s2²
a) To find the test statistics, use the formula:
Test statistics = 1.7037
b) P-value:
Sham: degrees of freedom
Magnet: degrees of freedom
The critical values:
[Za/2, df1, df2)], [(1 - Za/2), df1, df2]
![f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]](https://tex.z-dn.net/?f=%20f%5B0.05%2F2%2C%2019%2C%2019%5D%2C%20f%5B%281%20-%200.05%2F2%29%2C%2019%2C%2019%5D%20)
![f[0.025, 19, 19], f[0.975, 19, 19]](https://tex.z-dn.net/?f=%20f%5B0.025%2C%2019%2C%2019%5D%2C%20f%5B0.975%2C%2019%2C%2019%5D%20)
The rejection region:
Reject H0, if F < 0.3958 or if F > 2.526
c) Conclusion:
Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.
There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets
Answer:
y=3÷9
Step-by-step explanation:
2x-9y=11
or,2×7-9y=11
or,14-11=9y
or,3÷9=y
Answer:
10m x 15m
Step-by-step explanation:
You are given some information.
1. The area of the garden: A₁ = 150m²
2. The area of the path: A₂ = 186m²
3. The width of the path: 3m
If the garden has width w and length l, the area of the garden is:
(1) A₁ = l * w
The area of the path is given by:
(2) A₂ = 3l + 3l + 3w + 3w + 4*3*3 = 6l + 6w + 36
Multiplying (2) with l gives:
(3) A₂l = 6l² + 6lw + 36l
Replacing l*w in (3) with A₁ from (1):
(4) A₂l = 6l² + 6A₁ + 36l
Combining:
(5) 6l² + (36 - A₂)l +6A₁ = 0
Simplifying:
(6) l² - 25l + 150 = 0
This equation can be factored:
(7) (l - 10)*(l - 15) = 0
Solving for l we get 2 solutions:
l₁ = 10, l₂ = 15
Using (1) to find w:
w₁ = 15, w₂ = 10
The two solutions are equivalent. The garden has dimensions 10m and 15m.