Answer:
acute
Step-by-step explanation:
Given a plane:
normal vector <2,4,-3>
passes through point (-1,3,5)
The equation of the plane is
Π : 2(x-(-1))+4(y-3)-3(z-5)=0
expand and simplify
Π : 2x+4y-3z+5=0
Answer:
The position P is:
ft <u><em> Remember that the position is a vector. Observe the attached image</em></u>
Step-by-step explanation:
The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity
is:

Where
is the initial height = 0 for this case
We know that the initial velocity is:
82 ft/sec at an angle of 58 ° with respect to the ground.
So:
ft/sec
ft/sec
Thus

The height after 2 sec is:


Then the equation that describes the horizontal position of the ball is

Where
for this case
ft / sec
ft/sec
So

After 2 seconds the horizontal distance reached by the ball is:

Finally the vector position P is:
ft
Answer:
The correct options are A and B.
Step-by-step explanation:
The angles are represented by three capital letters like: ABC or DEF. In these names middle letter represent the vertex of the angle.
The order or first and last letter does effect the angle. It means

We have to find the angle with a vertex at Y. It means the middle letter must be Y.
In option A and B the middle letter is Y, therefore both options are correct.
In option C and D the middle letter is not Y, therefore both options are incorrect.
10, 8, 6, 4,…
-2 -2 -2
a(n) = a₁ + d(n - 1)
a(n) = 10 - 2(n - 1)
a(n) = 10 - 2(n) + 2(1)
a(n) = 10 - 2n + 2
a(n) = -2n + 10 + 2
a(n) = -2n + 12