1) a^2 = c^2 - b^2
a^2 = 5^2 - 4^2
a^ 2 = 9
(Square root 9)
a = 3
2) a^ 2 + b^2 = c^2
8^2 + 4^2 = c^2
80 = c^2
(Square root of 80)
C = 8.9 cm
3) a^2 + b^2 = c^2
6^2 + 2^2 = c^2
40 = c^2
(Square root of 40)
C = 6.3 cm
4) a^2 + b^2 = c^2
10^2 + 24^2 = c^2
676 = c^2
(Square root of 676)
C = 26
5) a^2 + b^2 = c^2
6^2 + 5^2 = c^2
61 = c^2
C = 7.8cm
6) a^2 + b^2 = c^2
12^2 + 12^2 = c^2
288 = c^2
C = 16.97cm
7) 8^2 + 6^2 = c^2
100 = c^2
C = 10
8) a^2 = c^2 - b^2
a^2 = 25^2 - 20^2
a^2 = 225
a = 15
9) a^2 = 14^2 - 9^2
a^2 = 115
a = 10.7cm
10) a^2 = 20^2 - 15^2
a^2 = 175
a = 13.2cm
11) Does 15^2 + 8^2 = 17^2?
289 = 289
Yes it’s a right angled triangle because 15^2 + 8^2 = 17^2
Do the same for the others
12) 7^2 + 5^2 = 74
9^2 = 81
So it’s not a right angled triangle
13) 5^2 + 12^2 = 169
13^2 = 169
It is a right angled triangle
14) 9^2 + 12^2 = 225
16^2 = 256
Not a right angled triangle
15) 10^2 + 24^2 = 676
26^2 = 676
It is a right angled triangle
16) 2^2 + 2^2 = 8
3^2 = 9
Not a right angled triangle
(x+2)^4=((x+2)^2)^2(x+2)^2=(x^2+2^2+2(x)(2))= x^2+4+4x (x^2+4+4x)^2=(x^2+4+4x)(x^2+4+4x) = x^4+4x^2+4x^3+4x^2+16+16x+4x^3+16x+16x^2=x^4+4x^3+4x^3+4x^2+16x^2+4x^2+16x+16x+16=x^4+8x^3+24x^232x+16
The number is 1
1 + 1 = 2
2(2) = 4
1 is your answer
hope this helps
Answer:
F. 6s > 4s +8
Step-by-step explanation:
From a reference point at the beginning of the track, Ward's car will be located 4s+8 feet down the track after s seconds. That is, it starts 8 feet down the track, and increases its distance by 4 feet every second.
From the same reference point, Heskey's car will be located 6s feet down the track after s seconds. Its distance starts from zero and is increasing at the rate of 6 feet every second.
For Heskey's distance to exceed Ward's distance you want ...
6s > 4s +8 . . . . . . matches choice F
