Five times a number k minus 9 is two thirds of a number j. solve for j

An item on sale costs 10% of the original price. The original price was $69 . Wats the price now

9966 [12]

Answer:

$62.10

Step-by-step explanation:

The difference is $6.90

Hope this helps.

4 0

3 years ago

Read 2 more answers

Bryan created a scale drawing of his rectangular bedroom. His drawing had dimensions of 6 inches by 8 inches. If the scale that

vlabodo [156]

Answer:

56 feet

Step-by-step explanation:

If 1 inch = 2 feet, we can first find the actual dimensions of his room by multiplying the number of inches by 2.

6(2)

= 12

8(2)

= 16

So, the actual dimensions of his room are 12 feet by 16 feet.

To find the perimeter, use the perimeter formula, P = 2l + 2w.

Plug in the length and width:

P = 2l + 2w

P = 2(12) + 2(16)

P = 24 + 32

P = 56

So, the perimeter of his actual room is 56 feet.

6 0

2 years ago

Please help! acellus

ch4aika [34]

Answer:

The number that belongs in the green box is equal to 909.

General Formulas and Concepts:
Algebra I

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Trigonometry

[Right Triangles Only] Pythagorean Theorem:
$\displaystyle a^2 + b^2 = c^2$

a is a leg
b is another leg
c is the hypotenuse

Step-by-step explanation:

Step 1: Define

Identify given variables.

a = 30

b = 3

c = x

Step 2: Find x

Let's solve for the general equation that allows us to find the hypotenuse:

[Pythagorean Theorem] Square root both sides [Equality Property]:
$\displaystyle \begin{aligned}a^2 + b^2 = c^2 \rightarrow c = \sqrt{a^2 + b^2}\end{aligned}$

Now that we have the formula to solve for the hypotenuse, let's figure out what x is equal to:

[Equation] Substitute in variables:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2}\end{aligned}$
Evaluate:
$\displaystyle \begin{aligned}c & = \sqrt{a^2 + b^2} \\x & = \sqrt{30^2 + 3^2} \\& = \boxed{ \sqrt{909} } \\\end{aligned}$