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3 years ago

In a 10 x 10 grid that represents 800, one square represents

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

3 0

Each square represents 8

If it is 10×10 then there is 100 squares

800÷100=8

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Cleo wants to jion a gym. There is an initiation fee of $24.99, and each month of membership costs $12.50. If Cleo pays $174.99,

mamaluj [8]

Answer: The membership will last for 12 months.

Step-by-step explanation:

Let x represent the number of months that the membership would last.

Cleo wants to join a gym. There is an initiation fee of $24.99, and each month of membership costs $12.50. This means that the total cost of using the gym for x months would be expressed as

12.5x + 24.99

If Cleo pays $174.99, it means that

12.5x + 24.99 = 174.99

12.5x = 174.99 - 24.99

12.5x = 150

x = 150/12.5

x = 12

6 0

3 years ago

15 points for someone who can answer & explain this to me thanks

iris [78.8K]

Answer:

see explanation

Step-by-step explanation:

Given

$\frac{9}{a^2+9a+20}$ , $\frac{7a}{a^2+11a+28}$

Factor the denominators of both fractions

$\frac{9}{(a+4)(a+5)}$ , $\frac{7a}{(a+4)(a+7)}$

The lowest common denominator of both fractions is (a + 4)(a + 5)(a + 7)

Multiply numerator/denominator of first fraction by (a + 7)

Multiply numerator/denominator of second fraction by (a + 5 )

$\frac{9(a+7)}{(a+4)(a+5)(a+7)}$ , $\frac{7a(a+5)}{(a+4)(a+5)(a+7)}$ , then

$\frac{9a+63}{(a+4)(a+5)(a+7)}$ , $\frac{7a^2+35a}{(a+4)(a+5)(a+7)}$

8 0

2 years ago

Please help! A-level maths.

astra-53 [7]

$x+y=k\implies y=k-x$

Substitute this into the parabolic equation,

$k-x=6-(x-3)^2\implies x^2-7x+(k+3)=0$

We're told the line $x+y=k$ intersects $C$ twice, which means the quadratic above has two distinct real solutions. Its discriminant must then be positive, so we know

$(-7)^2-4(k+3)=49-4(k+3)>0\implies k$

We can tell from the quadratic equation that $C$ has its vertex at the point (3, 6). Also, note that

$-1\le\sin t\le1\implies3\le3+2\sin t\le5\implies3\le x\le5$

and

$-1\le\cos2t\le1\implies2\le4+2\cos2t\le6\implies2\le y\le6$

so the furthest to the right that $C$ extends is the point (5, 2). The line $x+y=k$ passes through this point for $2+5=k\implies k=7$ . For any value of $k$ , the line $x+y=k$ passes through $C$ either only once, or not at all.