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Nuetrik [128]
3 years ago
13

ASAP -will mark brianist

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
5 0

Answer:

20-12

35-21

40-24

Step-by-step explanation:

You times both numbers by the same value

Oksana_A [137]3 years ago
5 0

Answer:

1st is 12

2nd is 35

3rd is 40

Step-by-step explanation:

You might be interested in
What is the percent of increase from 30 to 54?<br><br> Write your answer using a percent sign (%).
just olya [345]
54 - 30 = 24
Take the orginal number and place on the bottom
The orginal number is 30
24/30, if you need to simply find this number it will be 4/5
When you divide 4/5 it will be .80 or 80%
5 divide by 4 is equal to
Answer: 80%
Hope this help
7 0
3 years ago
How do I solve out 5x188
mihalych1998 [28]

Answer:

940

Step-by-step explanation:

 188

<u>×    5</u>

 940

--------------------------------------------------------

8 * 5 = 40

Carry the 4 to the next 8

8 * 5 = 40

Add the 4 to the 40

40 + 4 = 48

Carry the 4 to the 1

1 * 5 = 5

Add the 4

5 + 9

= 940

*Hope this helps .^.*

5 0
3 years ago
Round 1.07 to the tenths place.
galben [10]
Answer: 1.10
Work: 5 or more raise the next digit, 4 or less keep it
5 0
3 years ago
Ntial)
luda_lava [24]
B is the correct answer
6 0
3 years ago
Factor completely x^8- 16.
Nataly_w [17]

Answer:

Step-by-step explanation:


So in this example we'll be using the difference of squares which essentially states that: (a-b)(a+b)=a^2-b^2 or another way to think of it would be: a-b=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}). So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:

x^8-16 = (x^4-4)(x^4+4)

Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:

x^4-4 = (x^2-2)(x^2+2)

So completely factored form is: (x^2-2)(x^2+4)(x^4+4)

I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because x^2+4 = x^2-(-4). and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: x^4+4 = x^4 - (-4) = (x^2-\sqrt{-4})(x^2+\sqrt{-4}) = (x^2-2i)(x^2+2i) just something that might be useful in some cases.

7 0
2 years ago
Read 2 more answers
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