<span>w+6tw=11-w
</span>
<span>Let's solve for w.
</span><span><span>
w+<span><span>6t</span>w</span></span>=<span>11−w
</span></span>
Step 1: Add w to both sides.<span><span><span><span><span>
6t</span>w</span>+w</span>+w</span>=<span><span><span>−w</span>+11</span>+w</span></span><span><span><span><span>
6t</span>w</span>+<span>2w</span></span>=11</span><span>
Step 2: Factor out variable w.
</span><span><span>
w<span>(<span><span>6t</span>+2</span>)</span></span>=11</span><span>
Step 3: Divide both sides by 6t+2.
</span><span><span>
w<span>(<span><span>6t</span>+2</span>)</span></span><span><span>/6t</span>+2</span></span>=<span>11/<span><span>6t</span>+2</span></span>
Answer: 11/6t+2
False
A function can’t have 2 y-intercepts so y is not a function of x
The last one y=2x-5 if you plug the points into the x and y values you can see this equation works for both points.
Answer:
24 inches
Step-by-step explanation:
Answer:
Function 1 has the larger maximum at (4, 1)
Explanation:
After observation, graph of function 1 has vertex at Maximum (4, 1)
In order to find vertex of function 2, complete square the equation.
f(x) = -x² + 2x - 3
f(x) = -(x² - 2x) - 3
f(x) = -(x - 1)² - 3 + (-1)²
f(x) = -(x - 1)² - 2
Vertex form: y = a(x - h)² + k where (h, k) is the vertex
So, here for function 2 vertex: Maximum (1, -2)
<h3>Conclusion:</h3>
Function 1 = Maximum (4, 1), Function 2 = Maximum (1, -2)
Function 1 has greater maximum value of (4, 1) as "1 is greater than -2"
