Question

If the nerve cell connecting the spinal cord to your feet is 1.4 m long, and the nerve impulse speed is 25 m/s, how many seconds does it take for the nerve signal to travel this distance?

Answer 1

Answer:

Time taken by the nerve signal for travelling this distance $= 0.056$ seconds

Explanation:

Given,

The length of nerve cell connecting the spinal cord to the feet $= 1.4 m$

Speed of nerve impulse $25\frac{m}{s}$

Time taken for  the nerve signal to travel this distance is equal to the total " length of nerve cell connecting the spinal cord to the feet" divided by "speed of nerve impulse"

Substituting the given values in above equation, we get -

$\frac{1.4}{25}$

$= 0.056$ seconds.

Thus , time taken by the nerve signal for travelling this distance $= 0.056$ seconds