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ololo11 [35]
4 years ago
12

If the nerve cell connecting the spinal cord to your feet is 1.4 m long, and the nerve impulse speed is 25 m/s, how many seconds

does it take for the nerve signal to travel this distance?
Biology
1 answer:
liubo4ka [24]4 years ago
3 0

Answer:

Time taken by the nerve signal for travelling this distance = 0.056 seconds

Explanation:

Given,

The length of nerve cell connecting the spinal cord to the feet = 1.4 m

Speed of nerve impulse 25\frac{m}{s}

Time taken for  the nerve signal to travel this distance is equal to the total " length of nerve cell connecting the spinal cord to the feet" divided by "speed of nerve impulse"

Substituting the given values in above equation, we get -

\frac{1.4}{25}

= 0.056 seconds.

Thus , time taken by the nerve signal for travelling this distance = 0.056 seconds

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