Answer:
Star A is 3.343 times hotter than star B.
Explanation:
It is known that the luminosity of a star is proportional to its effective temperature to the 4th power. This means that the ratio between the brightness of stars A and B is equal to the ratio between their temperatures to the 4th power:
![125=T^4\\T=\sqrt[4]{125}\\T=3.343](https://tex.z-dn.net/?f=125%3DT%5E4%5C%5CT%3D%5Csqrt%5B4%5D%7B125%7D%5C%5CT%3D3.343)
Star A is 3.343 times hotter than star B.
Answer:
To correctly answer it.
Explanation:
Scientists need to gather information on a problem before solving it because it they don't gather the required information then they will end up with incorrect solutions for the problem.
Hertzsprung-Russell diagram to describes each star will be:
The star can no longer support nuclear fission because is has exhausted the supply of hydrogen - Sirius B
The stars hydrogen supply is running low so it is using hydrogen from outside the core. - Betelgeuse.
The stars experiencing nuclear fusion a score. - the sun.
<h3>What is Hertzsprung-Russell?</h3>
It should be noted that Hertzsprung-Russellb shows the relationship that exists between the temperature of a star and the luminosity.
In this case, the star that can no longer support nuclear fission because is has exhausted the supply of hydrogen is Sirius B.
The star where thd hydrogen supply is running low so it is using hydrogen from outside the core is the Betelgeuse and the stars experiencing nuclear fusion a score is the sun.
Learn more about Hertzsprung-Russell on
brainly.com/question/21131847
#SPJ1
