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Free_Kalibri [48]
3 years ago
14

Help with Algebra 2: 1.

20%7D" id="TexFormula1" title="\frac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }" alt="\frac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }" align="absmiddle" class="latex-formula">
2.3\sqrt[4]{(x-2)^3} -4=20

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }

Note that

\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}

When dividing \sqrt[7]{x^5} by \sqrt[4]{x^2}, we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}

and the result is x^{\frac{3}{14}}=\sqrt[14]{x^3}

2. Given equation 3\sqrt[4]{(x-2)^3} -4=20

Add 4:

3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24

Divide by 3:

\sqrt[4]{(x-2)^3} =8

Rewrite the equation as:

(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3

Hence,

\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18

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garri49 [273]

Answer:

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Step-by-step explanation:

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Since the 2 hemispheres have the same radius, we can simply find the volume of a sphere.

Volume of sphere

=  \frac{4}{3}( \pi)( {12}^{3} )

= 2304\pi \: in^{3}

Volume of solid

= volume of cylinder -volume of 2 hemispheres

Let's find the volume of the cylinder.

\boxed{voume \: of \: cylinder = \pi {r}^{2}h }

Volume of cylinder

= \pi( {12}^{2} )(24)

= 3456\pi \: in^{3}

Thus, volume of solid

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3 years ago
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Bas_tet [7]

The question is:

Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements.

a. Jerry does not have an Internet connection.

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c. Jan and Sharon have never chatted over the Internet.

d. No one in the class has chatted with Bob.

e. Sanjay has chatted with everyone except Joseph.

f. Someone in your class does not have an Internet connection.

g. Not everyone in your class has an Internet connection.

h. Exactly one student in your class has an internet connection.

i. Everyone except one student in your class has an Internet connection.

j. Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class.

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l. There are two students in your class who have not chatted with each other over the Internet.

m. There is a student in your class who has chatted with everyone in your class over the Internet.

n. There are at least two students in your class who have not chatted with the same person in your class.

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Note that: Because the arguments are variables, we write

Ix = I(x)

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a. Jerry does not have an Internet connection.

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b. Rachel has not chatted over the internet with Chelsea.

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g. Not everyone in your class has an internet connection.

~∀x Ix.

h. Exactly one student in your class has an internet connection.

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i. Everyone except one student in your class has an internet connection. This means exactly one student does not have a connection.

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j. Everyone in your class with an internet connection has chatted over the internet with at least one other student in your class.

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∀x (Ix → ∃y (Cxy))

k. Someone in your class has an internet connection but has not chatted with anyone else in your class.

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l. There are two students in your class who have not chatted with each other over the internet.

∃x ∃y (x ≠ y∧~Cxy).

m. There is a student in your class who has chatted with everyone in your class over the internet.

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o. There are two students in the class who between them have chatted with everyone else in the class.

∃x ∃y (x ≠ y ∧ ∀z (Cxz ∨ Cyz)).

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therefore, your answer is 9/20!

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