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3 years ago

A number t multiplied by −4 is at least −25 .

Mathematics

2 answers:

Olin [163]3 years ago

6 0

+7 would be the answer i believe

EastWind [94]3 years ago

6 0

I'm guessing it'll be or somewhere around t(-4)=< -25

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Rewrite in simplest radical form square root of x times the fourth root of x. Show each step of your process.

Ipatiy [6.2K]

Answer:

$\sqrt[4] {x^3}$

Step-by-step explanation:

At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:

$\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}$

Alternatively, if you're allowed to use rational exponents, we can convert everything:

$\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}$

5 0

1 year ago

A circle has a radius of 6 cm. What is the area of the circle? (Use 3.14 for pi)

vampirchik [111]

Answer:

113.04 cm²

Step-by-step explanation:

area of a circle= πr²

= 3.14 x 6²

=3.14 x 36

= 113.04 cm²

5 0

3 years ago

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Solved

6 0

3 years ago

Which of the following is equivalent to log base(25) 125?

Scilla [17]

The solution to the problem is as follows:

x = log (25) (125)

125 = 25^x

log 125 = x log 25

x = 3/2

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

3 0

3 years ago

Read 2 more answers

What is the answer i need help

Katyanochek1 [597]

Answer:

Step-by-step explanation:

3 0

3 years ago