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3 years ago

14

Did you mean: resolver ejercicio de matematicas:el interior de un parque es un cuadrado cuya area es de 8,100 pies cuadrados. se

reparará con grama nueva el area triangular sombreada entre la primera y la tercera base. ¿ cual es el area en pies cuadrados que se reparara?

1 answer:

riadik2000 [5.3K]3 years ago

7 0

Answer:

$4,050\ ft^2$

Step-by-step explanation:

<u><em>The question in English is</em></u>

The interior of a park is a square whose area is 8,100 square feet. The shaded triangular area between the first and third base will be repaired with new grass.

what is the area in square feet that will be repaired?

<u>The picture of the question in the attached figure</u>

we know that

The diagonal in a square divide the square into two congruent right triangles

so

The shaded triangular area is equal to divide the area of the square by 2

$\frac{8,100}{2}=4,050\ ft^2$

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The inverse for f(x)=-.75x

irina [24]

It would be $-\frac{4x}{3}$ .

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3 years ago

You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s

fredd [130]

Answer:

Time spent rowing down stream $=100\ seconds$

Speed of boat in still water $=14\ ms^{-1}$

Step-by-step explanation:

Let speed of boat in still water be $= x\ ms^{-1}$

Speed of current $= 10\ ms^{-1}$

Speed of boat down stream = $\textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}$

Distance rowed down stream = 2400 m

Time spent rowing down stream = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$ = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$

Speed of boat up stream = $\textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}$

Distance rowed up stream = $\frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m$

Time spent rowing up stream = $\frac{Distance}{Speed}=\frac{400}{x-10}\ s$

We know that,

$\textrm{Time spent rowing down stream =Time spent rowing up stream}$

So,

$\frac{2400}{x+10}=\frac{400}{x-10}$

Cross multiplying

$2400(x-10)=400(x+10)$

Dividing both sides by $400$

$\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}$

$6(x-10)=x+10$

$6x-60=x+10$

Adding 60 to both sides.

$6x-60+60=x+10+60$

$6x=x+70$

Subtracting both sides by $x$

$6x-x=x+70-x$

$5x=70$

Dividing both sides by 5.

$\frac{5x}{5}=\frac{70}{5}$

∴ $x=14$

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Time spent rowing down stream = $\frac{2400}{14+10}=\frac{2400}{24}=100\ s$

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3 years ago

A migrating bird flies 700 miles in 1414 hours. How many miles does it fly in 33 hours

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In 1414 hours it covered 700 miles

In 1 hour it would have covered (700/1414) mile

In 33 hours it will then cover : 700/1414 * 33 = 16.34

So in 33 hours it will cover ≈ 16.34 miles.

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3 years ago

Help please!! Stuck on this question!! ∠ABC is adjacent to ∠CBD. If the m∠ABC=4x+23, m∠CBD=6x+7, and m∠ABD=130°, what is the mea

Ulleksa [173]

Answer:

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Step-by-step explanation:

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3 0

3 years ago

$3000 is invested at 3% annual interest for 3 years.<br> a. Simple Interest b. Compound Interest

stich3 [128]

Answer:

a. $270

b. $3,278.18

Step-by-step explanation:

Given that

The principal amount is $3,000

Annual rate of interest is 3%

And, the time period is 3 years

We need to find out the simple interest & compound interest

The following formulas should be used

a. For simple interest

= Principal × rate of interest × time period

= $3,000 × 3% × 3 years

= $270

b. For compound interest

= Principal × (1 + rate of interest)^time period

= $3,000 × (1 + 0.03)3

= $3,000 × 1.03^3

= $3,278.18

8 0

2 years ago