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Reil [10]
4 years ago
9

What is 2.602 as a mixed number

Mathematics
1 answer:
MrRa [10]4 years ago
6 0
I think that it is 2 602/1000
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What expression is equivalent to 2x+3y-x-(8+1)
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Step-by-step explanation:

2x + 3y - x - 9

x + 3y - 9

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3 years ago
Alpha Printing will make 400 brochures for $60. Omega Printing will make 1,000 brochures for $60. How much money will you save o
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Alpha Printing: 400 / 60 =6.6...

Omega Printing: 1,000 / 60 = 16.6...

16.6

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Maria needs 22 cups of milk to make banana milk shakes for her friends. If 1 pint is equal to 2 cups, how many pints of milk sho
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22×2 =44 is the answer
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3 years ago
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(HELP WITH THIS )Suppose ages of cars driven by company employees are normally distributed with a mean of 8 years and a
8090 [49]

Answer:

Let say 75% of  cars older than age  = Y  years

than 25 % cars of age less than Y Years

Z score corresponding to 25 %  =  -0.674

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Value = Y

Mean = 8

SD = 3.2

Z score = -0.674

-0.674 = (Y - 8)/3.2

=> Y =5.84 Years

=> Y ≈ 5.9 Years

Approximately 75% of cars driven by company employees are older than  about 5.9 years

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4 years ago
In 2008, data from the Center for Disease Control revealed that 28.5% of all male teenagers, aged 18-19 and attending U.S. colle
m_a_m_a [10]

Answer:

a) H0 : u = 28.5%

H1 : u < 28.5%

b) critical value = - 1.645

c) test statistic Z= - 1.41

d) Fail to reject H0

e) There is not enough evidence to support the professor's claim.

Step-by-step explanation:

Given:

P = 28.5% ≈ 0.285

X = 210

n = 800

p' = \frac{X}{n} = \frac{210}{800} = 0.2625

Level of significance = 0.05

a) The null and alternative hypotheses are:

H0 : u = 28.5%

H1 : u < 28.5%

b) Given a 0.05 significance level.

This is a left tailed test.

The critical value =

-Z_0.05 = -1.645

The critical value = -1.645

c) Calculating the test statistic, we have:

Z = \frac{p' - P}{\sqrt{\frac{P(1-P)}{n}}}

Z = \frac{0.2625 - 0.285}{\sqrt{\frac{28.5(1-28.5)}{800}}}

Z = -1.41

d) Decision:

We fail to reject null hypothesis H0, since Z = -1.41 is not in the rejection region, <1.645

e) There is not enough evidence to support the professor's claim that the proportion of obese male teenagers decreased.

5 0
4 years ago
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