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Reil [10]
4 years ago
9

What is 2.602 as a mixed number

Mathematics
1 answer:
MrRa [10]4 years ago
6 0
I think that it is 2 602/1000
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I need help with this question please!!!
stealth61 [152]

Answer:

Step-by-step explanation:

Each point of function b(x) is shifted by rule

x -----> ( x - 2 )

and

y -----> (y + 3)

( - 1.5, 0) ------> (- 3.5, 3)

(- 1, - 1) -----> ( - 3, 2)

(0, - 2) ------> ( - 2, 1)

(1, - 1) -----> ( - 1, 2)

(2, 3) -----> (0, 6)

(4, 7) -----> (2, 10)

......

5 0
3 years ago
How many significant figures does 0290<br> have?
docker41 [41]
Two significant figures.
The trailing zero is not significant
7 0
4 years ago
Assume that y varies inversely
Marina86 [1]

Answer:

y = 2

Step-by-step explanation:

y varies inversely with x setup is:

y = k/x

7 = \frac{k}{2/3}  (find 'k')

k = 7/1 · 2/3

k = 14/3

use what you know about 'k' and 'x' to solve for 'y'

y = 14/3 ÷ 7/3  (remember to multiply by the reciprocal when dividing fractions)

y = 14/3 · 3/7

y = 2

3 0
3 years ago
The product of a number and its multiplicative inverse is __________.
Alinara [238K]

Answer:

(B). 1

Step-by-step explanation:

15 x 1/15 = 1.

7 0
3 years ago
A state requires that all boat licenses consist of the letter A or M followed by any five digits. What is the number of groups o
torisob [31]

Answer:

200000

Step-by-step explanation:

The boat licenses are strings of six elements. Let's count the number of ways of constructing such string with the given conditions.

There are 2 ways of choosing the first character of the string (A or M). The second character can be any digit, so there are 10 possible choices. The third character is also any digit, so it can be chosen in 10 ways. Similarly, the fourth character can be chosen in 10 ways, and the fifth character can be chosen in 10 ways.

By the product rule there are 2×10×10×10×10×10=2×10^5=200000 ways to choose all the characters. Every choice of characters becomes a unique string (boat license) thus the number of avaliable boat licenses is 200000.s

7 0
3 years ago
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