Answer:
Explanation:
<u>1) Calculate the volume of the water in the tank.</u>
- Area of the base of the tank: B = 7 ft × 4 ft = 28 ft²
- Height of the tank: H = 9 in = 9 in × 1 ft / 12 in = 0.75 ft
- Volume of the tank: V = area of the base × height = B × H = 28 ft² × 0.75 ft = 21 ft³.
<u>2) Calculate the weight of 21 ft³ of water.</u>
Since this is not a chemistry question but a math question, I will not use the fomula of density but set a proportion with one unknown:
- 62.4 lb / 1 ft³ = x / 21 ft³
Solve for x:
- x = 21 ft³ × 64 lb / ft³ = 1,310.4 lb.
So, rounding to the next integer, the water in the tank weighs 1,310 pounds, when it is full.
516 is the dividend, 3 is the divisor, 172 would be the quotient.
3 goes into 5 once with a 2 remainder, that 2 turns into 21 because of the 1 in 516 which 3 goes into seven times with a remainder of zero turning into 6, which 3 goes into twice, making the quotient 172.
172 times 3 is 516
Answer
whats the problem.
Step-by-step explanation:
I am going to build a chart this is best when using ratios
seniors junior total
7 4
*? *? *?
Totals 121
The way we fill out this chart is that we add the rows and multiply the columns.
So we add 7 + 4 and fill it in our chart we get 11
seniors junior total
7 4 11
*? *? *?
Totals 121
now to find the *? need to divide 121/11 to get *?
121/11 = 11
so now our chart looks like this
seniors junior total
7 4 11
11 11 11
Totals 121
Now we multiply each column
so
7 * 11 = 77
4*11 = 44
now our chart look like this
seniors junior total
7 4 11
11 11 11
Totals 77 44 121
so seniors get 77 spaces
and juniors get 44 spaces.
Answer:
Step-by-step explanation:whtyui
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