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3 years ago

Please please please please please please thank please please please help me please ASAP

Mathematics

1 answer:

atroni [7]3 years ago

4 0

Answer:

Step-by-step explanation:

3x^2 + 2(y-1)/x+y^2

3(4)^2 + 2(3-1)/4+3^2

3x16+2x2/4+9

48+4/13

52/13

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Step-by-step explanation:

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3 years ago

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3 years ago

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3 years ago

In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th

11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

Probability that the students passed the second exam = P(S) = 0.72

Probability that the students passed both exams = $P(F \bigcap S)$ = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = $\frac{P(A\bigcap B)}{P(B) }$

Similarly, P(S/F) = $\frac{P(S\bigcap F)}{P(F) }$ = $\frac{P(F\bigcap S)}{P(F) }$ {As $P(F \bigcap S)$ is same as $P(S \bigcap F)$ }

= $\frac{0.58}{0.74}$ = 0.784

Therefore, probability that he passed the second exam is 0.784 .

5 0

3 years ago