The function you seek to minimize is
()=3‾√4(3)2+(13−4)2
f
(
x
)
=
3
4
(
x
3
)
2
+
(
13
−
x
4
)
2
Then
′()=3‾√18−13−8=(3‾√18+18)−138
f
′
(
x
)
=
3
x
18
−
13
−
x
8
=
(
3
18
+
1
8
)
x
−
13
8
Note that ″()>0
f
″
(
x
)
>
0
so that the critical point at ′()=0
f
′
(
x
)
=
0
will be a minimum. The critical point is at
=1179+43‾√≈7.345m
x
=
117
9
+
4
3
≈
7.345
m
So that the amount used for the square will be 13−
13
−
x
, or
13−=524+33‾√≈5.655m
Answer: x=35
Step-by-step explanation: hi! i’m happy to help. subtract the three from both sides, multiply the entire problem by 5 to even out the x, and there’s your answer :)
Answer:
Length of the line segment RS is, 18 cm.
Step-by-step explanation:
Two points are drawn on a ruler. Point R is located at 8 cm and Point S is located at 26 cm.
So, length of the line segment RS is,
(26 - 8) cm\
= 18 cm
We know that on a ruler if two points A and B are at a cm and b cm respectively, then, length of AB
= AB =
cm .
Step-by-step explanation:
Hello there!
Just solve for x by combining like terms:
2x+18=20
2x=20-18
2x=2
x=1
:)