Answer:convergent
Step-by-step explanation:
Given
Improper Integral I is given as
integration of 
is
![I=1000\times \left [ e^x\right ]^{0}_{-\infty}](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20%5Cleft%20%5B%20e%5Ex%5Cright%20%5D%5E%7B0%7D_%7B-%5Cinfty%7D)
![I=1000\times I=\left [ e^0-e^{-\infty}\right ]](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20I%3D%5Cleft%20%5B%20e%5E0-e%5E%7B-%5Cinfty%7D%5Cright%20%5D)
![I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20%5Cleft%20%5B%20e%5E0-%5Cfrac%7B1%7D%7Be%5E%7B%5Cinfty%7D%7D%5Cright%20%5D)
so the integration converges to 1000 units
Answer:
D) commutative property of addition
Answer:
2 cups
Step-by-step explanation:
Given :
7x is an odd integer.
To Find :
The next odd integer as an algebraic expression in x.
Solution :
All positive integers are :
1 , 2 , 3 , 4 , 5 , ......
From the above series we noticed that every other odd number is 2 more than the previous one.
So , 7x is an odd number.
Therefore, next odd number is 7x + 2.
Hence, this is the required solution.
