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3 years ago

5

The population of a town is 6500 and is increasing at a rate of 4% per year. At this rate , approximately what will the city's p

opulation be in 4 years?

1 answer:

harina [27]3 years ago

3 0

6500 × 4% = 260
260 × 4 = 1040
6500 - 1040 = 5460 populations after 4 years

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Describe the pattern in each sequence and determine the next term of the sequence

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2 years ago

Select the relations that are functions.

Arlecino [84]

Answer:

Depending on how the input of each function defined,

The first choice $\left\lbrace(a, 1),\, (6, 1), \, (C, 1)\right\rbrace$ ,
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The fourth choice $\left\lbrace(a, a),\, (b, b), \, (c, c)\right\rbrace$

might be functions.

Step-by-step explanation:

A function between two sets (domain and range) should

be defined for all elements in the domain, and
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2 years ago

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3 years ago

This set of points is on the graph of a function.

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2 years ago

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Hello Shannonrodrigue. You can solve this by setting up an exponential growth equation.

$A = A_ob^t$
$3600 = 3000b^4$

Now we solve for b
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$\frac{3600}{3000} = \frac{3000b^{4}}{3000}$
$\frac{6}{5} = b^4$
$\sqrt[4]{\frac{6}{5}} = \sqrt[4]{b^4}$
$\sqrt[4]{\frac{6}{5}} = b$

Now that we have found b, we can use the equation $A = 3000b^t$ to predict how many bacteria will be present after 10 hours.
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2 years ago