Answer:
The distance that Mrs. Gilbertson's daughter walked was 188.4 feet
Step-by-step explanation:
Here we have that Mrs. Gilbertson's daughter walked round the circle 12 times where the diameter of the circle = 5 ft., therefore, the circumference of the circle, the distance walked round each of the 12 times = π·D
Where:
D = 5 ft
Hence, circumference = π × 5 = 3.14 × 5 = 15.7 ft
Therefore, by walking round the circle 12 times, the total distance that Mrs. Gilbertson's daughter walked = 12 × 15.7 = 188.4 ft.
