Which equation represents this number sentence?

The population of city A was approximately 243,000 and it increased by 8% in one year.what was the new population

777dan777 [17]

Answer:

262440

Step-by-step explanation:

108/100×243000

6 0

3 years ago

Can you help me solve these questions....please and thank you!

FromTheMoon [43]

42)
prime numbers are 41, 43, 47
answer
F. 3

35)
36 colored
faction 36/60 = 18/30 = 6/10 = 3/5

faction not equivalent to is 8/20

answer is C. 8/20

11)
answer is D. 18.21

cause 18.21 > 17.06 and 18.21 < 18.307

5 0

4 years ago

Solve the following system of equations. 2x + y = 3 x = 2y - 1 Make sure there are NO SPACES in your answer. Include a comma in

Natalka [10]

2x + y = 3
x = 2y - 1

solve for y in the first equation;
2x + y = 3
y = 3 - 2x

x = 2y - 1
x = 2(3 - 2x) - 1
x = -4x + 5

solve for x;
x = -4x + 5
x + 4x = 5
5x = 5
x = 1

solve for y;
y = 3 - 2x
y = 3 - 2(1)
y = 1

the answer is: x = 1, y = 1

hope this helps, God bless!

8 0

3 years ago

IMPORTANT! WILL VOTE BRAINLIEST!!!

nikdorinn [45]

Answer:

The value of the ve = 9m/sec

Step-by-step explanation:

From the given formula, it can be conclude that this is evenly accelerated movement.

First I will rewrite given formula

vi = √ ve∧2 - 2ad First we will square on both sides and get

vi∧2 = ve∧2 - 2ad Now we will add monom (+2ad) to both sides and get

vi∧2 + 2ad = ve∧2 -2ad + 2ad =>

ve∧2 = vi∧2 +2ad Now we will rooted both sides and get

ve = √vi∧2 + 2ad

Now we will replace given data vi=7m/sec, a=8m/s∧2 and d=2m in the last formula

ve= √7∧2 + 2*8*2 = √49+32 = √81 = 9

ve= 9m/sec

Good luck!!!

7 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$

>> Therefore, your answers are x = -4 or x = 2.

Learn more about quadratic equations:

brainly.com/question/27638369

6 0

2 years ago

Read 2 more answers