What is 6s + 18t + 3w =

What will you get if you cut a triangle perpendiculary

swat32

Answer:

2 triangles ?

Step-by-step explanation:

sorry if i got this wrong, when you cut it through the middle connecting the ends it give you two triangles?

3 0

3 years ago

Read 2 more answers

Write an expression to find the perimeter of<br> the rectangle below:<br> 2x - 3y<br> 3x - 1

LuckyWell [14K]

Answer:

2(5x-3y-1)

Step-by-step explanation:

perimeter of a rectangle formula:

2l+2w

l=length(2x-3y)5x

w=width(3x-1)

2(2x-3y)+2(3x-1)

4x-6y+6x-2

10x-6y-2

2) all of these numbers have a gcf of 2 so lets divide this equation by 2:

2(5x-3y-1)

hope this helps!

4 0

3 years ago

Domain and Range for the function f(x)=5IXI is

shutvik [7]

Answer:

The domain of the function f(x) is:

$\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

The range of the function f(x) is:

$\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

Given the function

$f\left(x\right)=5\left|x\right|$

Determining the domain:

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

It is clear that the function has undefined points nor domain constraints.

Thus, the domain of the function f(x) is:

$\mathrm{Domain\:of\:}\:5\left|x\right|\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

Determining the range:

We also know that range is the set of values of the dependent variable for which a function is defined.

In other words,

Range refers to all the possible sets of output values on the y-axis.

We know that the range of an Absolute function is of the form

$c|ax+b|+k\:\mathrm{is}\:\:f\left(x\right)\ge \:k$

$k=0$

so

Thus, the range of the function f(x) is:

$\mathrm{Range\:of\:}5\left|x\right|:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

7 0

3 years ago

zheka24 [161]

Answer:

The circumference of the smaller circle is:

C = 2*pi*x/3

Step-by-step explanation:

We know that for a circle of radius R the circumference is given by:

C = 2*pi*R

where pi = 3.14...

Here we have two circles, A and B, where B is the larger circle and A is the smaller circle.

We know that:

The circumference of B is 3 times the circumference of A.

The radius of circle B is: OB = x

The radius of circle A is: OA

We want to find an expression of OA.

The circumference of circle B will be:

C(B) = 2*pi*OB = 2*pi*x

The circumference of circle A will be:

C(A) = 2*pi*OA

And we know that the circumference of circle B is 3 times the circumference of circle A, then:

C(B) = 3*C(A)

replacing the equations for the circumferences, we get:

2*pi*x = 3*(2*pi*OA)

dividing both sides by 2*pi, we get:

x = 3*OA

Now we want to solve this for OA, then we need to isolate it,

x/3 = OA

We can conclude that the radius of the smaller circle is equal to x/3.

Then the circumference of circle A is:

C(A) = 2*pi*x/3

5 0

3 years ago

What is the range of this function?<br> y =x + 1 - 8

diamong [38]

Answer:

range: {y | y>= -8)

Step-by-step explanation:

We have a radical here.

y = root( x + 1) - 8

y is defined as long as x+1 >= 0

so domain must be x > -1

y values would start from -8

and go upward.

range: {y | y>= -8)

7 0

3 years ago